In expression conversion from postfix to Infix _____________ data structure is used. a. Queue b. Graph c. Tree d. Stack
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In expression conversion from postfix to Infix _____________ data structure is used.
Queue
Graph
Tree
Stack
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- C++ Create a function called findData that will take the following parameter: “CHOICE, KEY”. Choice will determine which traversal will be used to traverse the tree for the second parameter KEY. If the KEY is found, the value will be displayed such that: “{KEY} was found!”. #include<iostream>#include<queue>struct treeNode{char dataItem;struct treeNode *firstChild;struct treeNode *nextSibling;};/* Preorder Traversalpreorder (v)visit(v)for each child w of vpreorder(w)*/void preorder(treeNode *currNode){if(currNode != NULL){std::cout << currNode->dataItem << " ";preorder(currNode->firstChild);preorder(currNode->nextSibling);}return;}/* Postorder Traversalpostorder (v)for each child w of vpostOrder(w)visit(v)*/void postorder(treeNode *currNode){if(currNode != NULL){preorder(currNode->firstChild);preorder(currNode->nextSibling);std::cout << currNode->dataItem << " ";}return;}/*Inorder Traversalif(v==NULL)…please convert to C languange #include<bits/stdc++.h>using namespace std; class tree{ //tree node public: int data; tree *left; tree *right;}; bool hasRootToLeafSum(tree *root, int s){ bool path=false; //declare boolean variable path //base condition checking if(root==NULL && s==0) return true; s-=root->data; //subtract current root value //checking whether leaf node reached and remaining sum =0 if(s==0 && root->left==NULL && root->right==NULL) return true; //recursively done for both subtrees if(root->left){//for left subtree path=path||hasRootToLeafSum(root->left, s); } if(root->right){//for right subtree path=path||hasRootToLeafSum(root->right, s); } return path;} tree* newnode(int data){ //creating new nodes tree* node = (tree*)malloc(sizeof(tree)); node->data = data; node->left = NULL; node->right = NULL;…Please fill in the blanks for C. // Singly Linked List #include<stdio.h> // Part 1 //Declare a node of character // each node has a value and a pointer that points to the next node struct charNode { __1__ val; __2__ __3__ next; }; /*This function takes the first pointer (head) and iterates through the list to print one character at a time.*/ __4__ printCharLL(__5__ __6__ curPtr) { printf("\nPrinting back the list: \n"); while(__7__ __8__ __9__) //condition to keep running the loop { printf("%c", __10__); //print the value using pointer, no spaces curPtr = __11__; //move the pointer to point to the next node in list, no spaces } printf("\n"); } // Part 2 //Declare a node of double // each node has a value and a pointer that points to the next node struct doubleNode { __12__ val; __13__ __14__ next; };…
- Stack: Stacks are a type of container with LIFO (Last In First Out) type of working, where a new element is added at one end and (top) an element is removed from that end only. Your Stack should not be of the fixed sized. It should be able to grow itself. So using the class made in task 1, make a class named as Stack, having following additional functionalities: bool empty() : Returns whether the Stack is empty or not. Time Complexity should be: O(1) bool full() : Returns whether the Stack is full or not. Time Complexity should be: O(1)int size() : Returns the current size of the Stack. Time Complexity should be: O(1)Type top () : Returns the last element of the Stack. Time Complexity should be: O(1) void push(Type) : Adds the element of type Type at the top of the stack. Time Complexity should be: O(1) Type pop() : Deletes the top most element of the stack and returns it. Time Complexity should be: O(1) Write non-parameterized constructor for the above class. Write Copy…#include <iostream> using namespace std; #define SIZE 5 //creating the queue using array int A[SIZE]; int front = -1; int rear = -1; //function to check if the queue is empty bool isempty() { if(front == -1 && rear == -1) return true; else return false; } //function to enter elements in queue void enqueue ( int value ) { //if queue is full if ((rear + 1)%SIZE == front) cout<<"Queue is full \n"; else { //now the first element is inserted if( front == -1) front = 0; //inserting element at rear end rear = (rear+1)%SIZE; A[rear] = value; } } //function to remove elements from queue void dequeue ( ) { if( isempty() ) cout<<"Queue is empty\n"; else //only one element if( front == rear ) front = rear = -1; else front = ( front + 1)%SIZE; } //function to show the element at front void showfront() { if( isempty()) cout<<"Queue is empty\n"; else cout<<"element at front is:"<<A[front]; } //function to display the queue void…C++ ProgrammingTopic: stacks queues and dequesBelow is the initial program of the main file, only modify the main file, sllstack file also provided for the reference of the main. See attached photo for instructions. main.cpp #include <iostream> #include <cstring> #include "sllstack.h" using namespace std; int main(int argc, char** argv) { SLLStack* stack = new SLLStack(); int test; string str; cin >> test; switch (test) { case 0: getline(cin, str); // PERFORM SOLUTION TO BRACKETS PROBLEM HERE // FYI: Place your variable declarations, if any, before switch. break; case 1: stack->push('a'); stack->push('b'); stack->push('c'); cout << stack->pop() << endl; cout << stack->pop() << endl; cout << stack->pop() << endl; cout << stack->isEmpty()…
- A)Draw the linked node structure created by the following program and , B)List the output of program. struct node{ struct node *left; char letter; struct node *right; }; typedef struct node *NODEPTR; NODEPTR getnode(void); void displayList(NODEPTR); void main() { NODEPTR p , list , save; char one; p=getnode(); p->letter='A'; list=p; p->right=p; p->left=p; save=list; for(int i=2;i<8;i+=2) { one='A'+ i; p=getnode(); p->letter=one; p->left=save; save->right=p; save=p; printf("Letter= %c\n",p->letter); } list->left=save; save->right=list; list=p; displayList(list); } void displayList(NODEPTR head) {NODEPTR save; printf("\nLIST\n"); save=head; do {printf("%c ",save->letter); save=save->left; }while(save!=head); } NODEPTR getnode() { NODEPTR q; q = (NODEPTR) malloc(sizeof(struct node));…20 T OR F An application programmer can prevent accessing an empty queue by using the isEmpty method in an if-statement to prevent such access.Stack: Stacks are a type of container with LIFO (Last In First Out) type of working, where a new element is added at one end and (top) an element is removed from that end only. Your Stack should not be of the fixed sized. It should be able to grow itself. bool empty() : Returns whether the Stack is empty or not. Time Complexity should be: O(1) bool full() : Returns whether the Stack is full or not. Time Complexity should be: O(1)int size() : Returns the current size of the Stack. Time Complexity should be: O(1)Type top () : Returns the last element of the Stack. Time Complexity should be: O(1) void push(Type) : Adds the element of type Type at the top of the stack. Time Complexity should be: O(1) Type pop() : Deletes the top most element of the stack and returns it. Time Complexity should be: O(1) Write non-parameterized constructor for the above class. Write Copy constructor for the above class. Write Destructor for the above class. Now write a global function show stack which…
- 1-) Write a function that swaps the contents of a stack and a queue. That is, the function takes the contents of 'stack' and places it in "queue' and the contents of "queue' into 'stack. You may use the stack and queue functions given in the class. Bir kuyruk ile bir stack'in içeriğini yer değiştiren bir fonksiyon yazınız. Sınmfta yazılan kuyruk ve stack fonksyionlarını kullanabilirsiniz. void swapQueueAndStack ( queue *q, stack *s)C++ PROGRAMMINGBinary Search Trees SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) #include "node.h" #include <iostream> using namespace std; class BSTree { node* root; int size; node* create_node(int num, node* parent) { node* n = (node*) malloc( sizeof(node) ); n->element = num; n->parent = parent; n->right = NULL; n->left = NULL; return n; } bool search(node* curr, int num) { if (curr == NULL) { return false; } if (num == curr->element) { return true; } if (num < curr->element) { return search(curr->left, num); } return search(curr->right, num); } node* search_node(node* curr, int num) { if (num ==…C++ PROGRAMMINGTopic: Binary Search Trees Explain the c++ code below.: It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed) node* left(node* p) { return p->left; } node* right(node* p) { return p->right; } node* sibling(node* p){ if(p != root){ node* P = p->parent; if(left(P) != NULL && right(P) != NULL){ if(left(P) == p){ return right(P); } return left(P); } } return NULL; } node* addRoot(int e) { if(size != 0){ cout<<"Error"<<endl; return NULL; } root = create_node(e,NULL); size++; return root; } node* addLeft(node* p, int e) { if(p->left == NULL){ node* newLeft =…