In exercising, a weight lifter loses 0.217 kg of water through evaporation, the heat required to evaporate the water coming from the weight lifter's body. The work done in lifting weights is 1.40*10^5 J. (a) Assuming that the latent heat of vaporization of perspiration is 2.42*10^6 J/kg, find the change in internal energy of the weight lifter. (b) Determine the minimum number of nutritional calories of food that must be consumed to replace the loss of internal energy. (1 nutritional calorie= 4186 J ).
In exercising, a weight lifter loses 0.217 kg of water through evaporation, the heat required to evaporate the water coming from the weight lifter's body. The work done in lifting weights is 1.40*10^5 J. (a) Assuming that the latent heat of vaporization of perspiration is 2.42*10^6 J/kg, find the change in internal energy of the weight lifter. (b) Determine the minimum number of nutritional calories of food that must be consumed to replace the loss of internal energy. (1 nutritional calorie= 4186 J ).
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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In exercising, a weight lifter loses 0.217 kg of water through evaporation, the heat required to evaporate the water coming from the weight lifter's body. The work done in lifting weights is 1.40*10^5 J. (a) Assuming that the latent heat of vaporization of perspiration is 2.42*10^6 J/kg, find the change in internal energy of the weight lifter. (b) Determine the minimum number of nutritional calories of food that must be consumed to replace the loss of internal energy. (1 nutritional calorie= 4186 J ).
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