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In Exercises 53-58, find the value of (f g)' at the given value of x. 53. f(u) = u + 1, u = g(x) = VI, x= 1 zises 54. f(u) = 1 1 u = g(x)%3D X = -1 1- x TTU 55. f(u) = cot- 10 u = g(x) 5V, x= 1 1 56. f(u) %3D и +- u = g(x) = Tx, x = 1/4 %3D %3D cos u

In Exercises 53-58, find the value of (f g)' at the given value of x. 53. f(u) = u + 1, u = g(x) = VI, x= 1 zises 54. f(u) = 1 1 u = g(x)%3D X = -1 1- x TTU 55. f(u) = cot- 10 u = g(x) 5V, x= 1 1 56. f(u) %3D и +- u = g(x) = Tx, x = 1/4 %3D %3D cos u

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Finding Numerical Values of Derivatives In Exercises 53-58, find the value of (f g' at the given value of x. 53. f(u) = u + 1, u = g(x) = V, x = 1 zises 54. f(u) = 1 %3D %3D 1 1 u = g(x) = x = -1 1- x 55. f(u) cot- 10 u = g(x) 5Vx, x 1 1 56. f(u) = u + cos u u = g(x) = 7x, x = 1/4 2u 57. f(u) u= g(x) = 10x + x + 1, x= 0 u + 1 58. f(u) = u = g(x) = - 1, %3D + 2.
Transcribed Image Text:Finding Numerical Values of Derivatives In Exercises 53-58, find the value of (f g' at the given value of x. 53. f(u) = u + 1, u = g(x) = V, x = 1 zises 54. f(u) = 1 %3D %3D 1 1 u = g(x) = x = -1 1- x 55. f(u) cot- 10 u = g(x) 5Vx, x 1 1 56. f(u) = u + cos u u = g(x) = 7x, x = 1/4 2u 57. f(u) u= g(x) = 10x + x + 1, x= 0 u + 1 58. f(u) = u = g(x) = - 1, %3D + 2.
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