In dilutions the amount of solute is held constant, but the volume is changed. Since (concentration)(volume) is equal to the amount of solute, we can derive an expression: M1V1=M2V2 where M represents molarity in mol/L and V is volume of the solution in Liters. THIS ONLY WORKS FOR DILUTIONS. Show you work and use the Molarity Simulation to check your answers. If you wanted 0.80L of a 0.25 M CuSO4 solution, what volume of 1.0 M CuSO4 solution would you dilute?
In dilutions the amount of solute is held constant, but the volume is changed. Since (concentration)(volume) is equal to the amount of solute, we can derive an expression: M1V1=M2V2 where M represents molarity in mol/L and V is volume of the solution in Liters. THIS ONLY WORKS FOR DILUTIONS. Show you work and use the Molarity Simulation to check your answers. If you wanted 0.80L of a 0.25 M CuSO4 solution, what volume of 1.0 M CuSO4 solution would you dilute?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In dilutions the amount of solute is held constant, but the volume is changed. Since (concentration)(volume) is equal to the amount of solute, we can derive an expression: M1V1=M2V2 where M represents molarity in mol/L and V is volume of the solution in Liters.
THIS ONLY WORKS FOR DILUTIONS.
Show you work and use the Molarity Simulation to check your answers.
-
If you wanted 0.80L of a 0.25 M CuSO4 solution, what volume of 1.0 M CuSO4 solution would you dilute?
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