5. The synthesis of aspirin (acetylsalicylic acid) is shown below. OH OH salicylic acid ("SA") ● H3C CH3 acetic anhydride ("AA") H3C OH aspirin ("AS") a) If you start with 0.25 grams of salicylic acid and 2.0 mL of acetic anhydride (d=1.08 g/mL), how much aspirin can you theoretically synthesize? + CH3COOH Show two calculations for the theoretical yield of aspririn: 1 with 0.25 g SA and 1 with 2.0 mL of AA. Compare the theoretical amounts of aspirin from both calculations to determine the limiting reagent. Circle/label the limiting reagent and its theoretical yield of aspirin

5. The synthesis of aspirin (acetylsalicylic acid) is shown below. OH OH salicylic acid ("SA") ● H3C CH3 acetic anhydride ("AA") H3C OH aspirin ("AS") a) If you start with 0.25 grams of salicylic acid and 2.0 mL of acetic anhydride (d=1.08 g/mL), how much aspirin can you theoretically synthesize? + CH3COOH Show two calculations for the theoretical yield of aspririn: 1 with 0.25 g SA and 1 with 2.0 mL of AA. Compare the theoretical amounts of aspirin from both calculations to determine the limiting reagent. Circle/label the limiting reagent and its theoretical yield of aspirin

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

32
16. Every year, oral rehydration therapy (ORT) –the feeding of an electrolyte solution -saves the lives of countless children worldwide who become severely dehydrated as a result of diarrhea. One requirement of the solution used is that it be isotonic with human blood. An ORT solution contains 3.5 g NaCl, 1.5 g KCI, 2.9 g Na3CgH507 (sodium citrate), and 20.0 g C6H1206 (glucose) per liter. What is the freezing point of this solution? You may assume that the density of the solution is 1.00 g/mL and that the freezing point depression constant (Kf) for water is 1.86 °C/m. -0.59 oC -1.86 oC 0.00 oC +0.51 оС -7.44 oC
N|OU|GA|OC| G b 01edu.co Maps In a_ A 2 F2 W # 3 80 F3 E > C □ $ 4 > F4 R OU Gd 2|GA|GV J|bs|G1|CS|UO A Question 29 of 31 reaction, the components of water (H-OH) are added across a carbon-carbon double bond (C=C). A) hydration B) hydrogenation C) bromination D) combustion E) elimination b 99 Aav % от бо 5 O F5 T B < 6 MacBook Air F6 Y D 7 0 F7 U * 8 DII F8 1 9 8 F9 0 0 F10 EE U Done P B Gr ☆ E 7 J F11 {
0. How many mL of 0.25M NaOH will be needed to neutralize 20 mL of stomach acid if stomach acid is 0.10 М НC1? NaOH + HCl → H2O+ NaCl (1) M(base)V(bases)= (1) M(acid)V(acid) (Im) 0) no
2. The solubility of barium hydroxide is listed in the solubility table as 5.60 g of barium hydroxide octahydrate at 15°C in 100 mL of water. Show your work for the following calculations. Give all values to three significant figures. ● ● How many moles of barium hydroxide is this? • How many grams of barium hydroxide can dissolve in 100 mL of water at 15°C? • What is the molarity of barium ions? What is the molarity of hydroxide ions?
AgNO(aq) + MgBr2(aq)---->AgBr(s) +_Mg(NO3)2 = identify the reactants,products and (aq) and -----> in otherwords what does (aq) mean and the ----> mean thanks
NH, Which inference about *3 can be supported by the solubility curves shown? Solubility Curves 150 140 130 120 NANO, KNO: 110 100 90 80 HCI 70 NH,CI 60 kc 50 40 NacI 30 KCIO, 20 10 SO 10 20 30 40 50 60 70 80 90 100 Temperature °C NH 3 is more soluble than KI. A NH 3 is a gas. B The solubility of NH 3 is not affected by temperature. Grams of solute / 100 g H,0
The solubility product constant for a certain metal fluoride, MF2 is Ksp = 1.2 × 10−6. Its molar mass is ℳ = 175.90 g/mol. What is its solubility in mol/L? Report your answer to TWO significant figures. Enter your answer in scientific notation using the appropriate boxes. Remember, a number like 1.6, in scientific notation is 1.6 × 100. Note: Your answer is assumed to be reduced to the highest power possible.
7.A solution is prepared by dissolving 0.030 mol of potassium perchlorate in 75 mL of hot water. KClO4 dissolves according to the equation KClO4 (s) ? K+ (aq) + ClO4- (aq). Will a precipitate form if the solution is cooled to 25oC? Assume that a negligible change in volume occurs during the operations. (Ksp = 8.9 x 10-3).
+ || Σ * 00 工 A 30.00 mL sample of an aqueous solution of HNO3 was titrated with 0.3621 M KOH. The HNO3 solution reacted with 23.72 mL of the KOH solution. The reaction is: HNO3 + KOH g KNO3 + H2O Calculate the number of moles of KOH used (NKOH = VKOH X MKOH), the number of moles of HNO3 that must have reacted (from the stoichiometric equation), and molarity of the nitric acid ( MHNO3 = 1HNO3/VHNO3). (ONΗΛ/ εΟNH MacBook Air 08 F3 000 F4 esc DD F1 F2 F5 F7 F8 F12 OLJ & $ 4 * # + delete 9. R Y { } tab %3D K os lock ret B C. control option command puewwoɔ option
NaHCO3 (aq) + CH3 COOH (aq) —> CO2 (g) + H2O (l) + CH3 COONa (aq) Calculate the molar concentration of 100ml of vinegar (CH3COOH) and 2.5 ml of baking soda (NaHCO3). Note that the concentration of table vinegar is about 1 mol/L and the density of baking soda is 2.2 g/cm3
Consider a slightly soluble salt with a general form of MX2(s) --> M*(aq) + 2X(aq). If its molar mass is 121 g/mol and K, = 1.5 x 108, what is its solubility in grams per 100 mL? O 0.0015 g/100 mL O 0.019 g/100 mL O 0.15 g/100 mL O 0.55 g/100 mL,