12. What is the Ke (to two decimal places) if the following reaction was reversed and all concentrations doubled? 30₂(8) = 203(aq) K = 1.76 × 10-3 112 Chemistry II A: 3.23 x 105 ©2022 F'22/S'23
12. What is the Ke (to two decimal places) if the following reaction was reversed and all concentrations doubled? 30₂(8) = 203(aq) K = 1.76 × 10-3 112 Chemistry II A: 3.23 x 105 ©2022 F'22/S'23
Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter2: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 2.77E: Determine rxnH 25 C for the following reaction: NO g O2 g NO2 g This reaction is a major...
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![12. What is the K. (to two decimal places) if the following reaction was reversed and all
concentrations doubled?
302(g) = 203(aq)
112
K = 1.76 x 10-3
Chemistry II
A: 3.23 × 105
©2022 F'22/S'23](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8e77b376-6a5c-4963-870c-f49a6e984799%2F13365de5-1cc0-4bb7-b6da-7069c7b314f1%2Fc3rurhl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:12. What is the K. (to two decimal places) if the following reaction was reversed and all
concentrations doubled?
302(g) = 203(aq)
112
K = 1.76 x 10-3
Chemistry II
A: 3.23 × 105
©2022 F'22/S'23
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