In determining automobile mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 38 mpg and a standard deviation of1.6 mpg. Complete parts a through e below.a. Find P(X<37).P(X<37)= 0.2643 (Round to four decimal places as needed.)Resb. Find P(3541).1)catioP(X>41) =(Round to four decimal places as needed.)Enter your answer in the answer box and then click Check Answer.2 partsremainingClear AllO Type here to searchacerF4F5F6F7F8F9F10F11F12PriScNumLkSyR&77885€6

a. The Z-score of a random variable X is defined as follows: Z = (X – µ)/σ. Here, µ and σ are the…

In determining automobile mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 38 mpg and a standard deviation of 1.6 mpg. Complete parts a through e below. a. Find P(X<37). P(X<37)= 0.2643 (Round to four decimal places as needed.) b. Find P(3541). tio P(X>41) = (Round to four decimal places as needed.)

In determining automobile mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 38 mpg and a standard deviation of 1.6 mpg. Complete parts a through e below. a. Find P(X<37). P(X<37)= 0.2643 (Round to four decimal places as needed.) b. Find P(3541). tio P(X>41) = (Round to four decimal places as needed.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

In determining automobile mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 35 mpg and a standard deviation of 1.9 mpg. Complete parts a through e below. a. Find P(X 37). P(X> 37) = (Round to four decimal places as needed.) d. Find P(X> 34). P(X> 34) =| (Round to four decimal places as needed.) e. Find the mileage rating that the upper 11% of cars achieve. The mileage rating that the upper 11% of cars achieve is mpg. (Round to two decimal places as needed.)
Answer part e only
In determining automobile mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 40mpg and a standard deviation of 1.8 mpg. Complete parts a through e below. b. Find P(36<X<44). P(36<X<44)= (Round to four decimal places as needed.)
A sample of 14 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is normal. The weight of each bag was then recorded. The mean weight was 2 ounces with a standard deviation of 0.12 ounces. The population standard deviation is known to be 0.1 ounce. x = σ = sx = n = n − 1 =
Which of the following statement is FALSE about X? ANOVA Source of variation df MS F stat P-value F crit Between Groups 5.2 a 2.6 Y 0.4177 3.8853 33.2 2.7667 Total 38.4 A. Within group variation В. Error C. Measure the variability between all group's mean and the grand mean. D. Measure the variability of the observed value around their respective group mean. А C D Answer
At a local store, 65 female employees were randomly selected and it was found that their mean monthly income was $625 with a standard deviation of $121.50, Seventy-five male employees were also randomly selected and their mean monthly income was found to be $667 with a standard deviation of $168.70, Test the hypothesis that male employees have a higher monthly income than female employees. Use a = 0.01. Use any method but follow the PHANTOMS acronym P-Parameter Statement H-Hypotheses A-Assumptions & Conditions N-Name the Test T-Test Statistic O-Obtain the P-Value or Critical Value M-Make a Decision about the Null Hypothesis S-State Your Conclusion About the Claim
Find the standard deviation, s, of sample data summarized in the frequency distribution table below by using the formula below, where x represents the class midpoint, f represents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviation to the standard deviation obtained from the original list of data values, 11.1. S= n[Σ(f.x²)]-[Σ(f.x)]² n(n-1) Interval Frequency Standard deviation = (Round to one decimal place as needed.) 20-29 2 30-39 3 1 40-49 1 C 50-59 2 60-69 8 70-79 32 80-89 38
Assume x is normally distributed with a mean of 2 and a standard deviation of 2. Find: a.P(X=2) b.P(X<2) c.P(X>=2) d.P(2 < X < 4)
A variable of two populations has a mean of 30 and a standard deviation of 18 for one of the populations and a mean of 30 and a standard deviation of 32 for the other population. Complete parts (a) through (c). a. For independent samples of size 9 and 16, respectively, find the mean and standard deviation of X₁ -X₂. (Assume that the sampling is done with replacement or that the population is large enough.) The mean of X₁ -X₂ is. (Type an integer or a decimal. Do not round.) The standard deviation of X₁-X₂ is (Round to four decimal places as needed.) b. Must the variable under consideration be normally distributed on each of the two populations for you to answer part (a)? Choose the correct answer below. OA. No, the variable does not need to be normally distributed for the formulas for the mean and standard deviation of x₁-x₂ to hold as long as the sample sizes are large enough, as long as the sampling is done with replacement. B. No, the formulas for the mean and standard deviation of…
Suppose that the weight of seedless watermelons is normally distributed with mean 6.2 kg. and standard deviation 1.5 kg. Let X be the weight of a randomly selected seedless watermelon. Round all answers to two decimal places. A. X ~ N( , ) B. What is the median seedless watermelon weight? kg. C. What is the Z-score for a seedless watermelon weighing 8 kg? D. What is the probability that a randomly selected watermelon will weigh more than 7 kg? E. What is the probability that a randomly selected seedless watermelon will weigh between 4 and 5 kg? F. The 80th percentile for the weight of seedless watermelons is kg.
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Let Z represent the reading of this thermometer at freezing. What reading separates the highest 5.66% from the rest? That is, if P(z > c) = 0.0566, find c. с — °C
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Let Z represent the reading of this thermometer at freezing. What reading separates the highest 46.73% from the rest? That is, if P(z > c) = 0.4673, find c. c = °C