In determining automobile mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 40 mpg and a standard deviation o 1.8 mpg. Complete parts a through e below. C a. Find P(X<39). P(X<39) = 0.2893 (Round to four decimal places as needed.) b. Find P(36 45). P(X>45)= 0.0027 (Round to four decimal places as needed.) d. Find P(X> 39). P(X>39) = 0.7107 (Round to four decimal places as needed.) e. Find the mileage rating that the upper 6% of cars achieve. The mileage rating that the upper 6% of cars achieve is mpg.

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Answer part e only

In determining automobile mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 40 mpg and a standard deviation of
1.8 mpg. Complete parts a through e below.
a. Find P(X<39).
P(X<39) = 0.2893 (Round to four decimal places as needed.)
b. Find P(36 < X<44).
P(36 < X <44) = 0.9736 (Round to four decimal places as needed.)
c. Find P(X> 45).
P(X>45)= 0.0027 (Round to four decimal places as needed.)
d. Find P(X> 39).
P(X>39) = 0.7107 (Round to four decimal places as needed.)
e. Find the mileage rating that the upper 6% of cars achieve.
mpg.
The mileage rating that the upper 6% of cars achieve is
(Round to two decimal places as needed.)
Transcribed Image Text:In determining automobile mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 40 mpg and a standard deviation of 1.8 mpg. Complete parts a through e below. a. Find P(X<39). P(X<39) = 0.2893 (Round to four decimal places as needed.) b. Find P(36 < X<44). P(36 < X <44) = 0.9736 (Round to four decimal places as needed.) c. Find P(X> 45). P(X>45)= 0.0027 (Round to four decimal places as needed.) d. Find P(X> 39). P(X>39) = 0.7107 (Round to four decimal places as needed.) e. Find the mileage rating that the upper 6% of cars achieve. mpg. The mileage rating that the upper 6% of cars achieve is (Round to two decimal places as needed.)
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