In Dalmatians, black spots are dominant to the condition of not having black spots. A black-spotted male whose mother did not have black spots is mated with a female that has no spots. They produce a litter of 6 puppies. Using a Punnett square, predict the number of each phenotype of puppy. Don't forget to define the alleles.

In Dalmatians, black spots are dominant to the condition of not having black spots. A black-spotted male whose mother did not have black spots is mated with a female that has no spots. They produce a litter of 6 puppies. Using a Punnett square, predict the number of each phenotype of puppy. Don't forget to define the alleles.

Name: In Dalmatians, black spots are dominant to the condition of not havin
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: In Dalmatians, black spots are dominant to the condition of not having black spots. A black-spotted malewhose mother did not have black spots is mated with a female that has no spots.They produce a litter of 6 puppies. Using a Punnett square, predic

Science Of Agriculture Biological Approach

5th Edition

ISBN:9780357229323

Author:Herren

Publisher:Herren

Chapter4: The Science Of Genetics

Section: Chapter Questions

Problem 1SLA

See similar textbooks

Similar questions

A walnut comb rooster is mated to three hens. Hen A, which has a walnut comb, has offspring in the ratio of 3 walnut to 1 rose. Hen B, which has a pea comb, has offspring in the ratio of 3 walnut to 3 pea to 1 rose to 1 single. Hen C, which has a walnut comb, has only walnut comb offspring. What are the genotypes of the rooster and the three hens?
When you decide to breed your Labrador retriever Molly and sell the puppies, you discover that two of Mollys four siblings have developed a hip disorder that is traceable to the action of a single recessive allele. Molly herself shows no sign of the disorder. If you breed Molly to a male Labrador that does not carry the recessive allele, can you assure a purchaser that the puppies will also be free of the condition? Explain your answer.
In cats, the locus for orange coat color is sex linked. Male cats that are black have the o+ allele, whereas those that are orange have the o allele. Females can be homozygous for the orange allele or homozygous for the black allele and will express each color, respectively. Heterozygous females are tortoise-shelled or calico, having orange and black patches. A calico cat, in addition to being heterozygous at the orange locus, also is either heterozygous or homozygous for the incompletely dominant, autosomal spotting allele (SS = large spots, Ss = small spots, ss = no spots). Manx tails are caused by a dominant trait that is lethal when homozygous. Long tails are the result of a homozygous recessive genotype. An orange male with small white spots and a manx tail is crossed to a calico female with small white spots and a manx tail. What is the probability of observing a solid black female with no spots and long tail? (Hint: All calico cats are female!)
a vaiety of snapdragon has flowers that can be white, red , yellow, and pink. yellow alleles are recessive to both white and red alleles. red and white alleles demonstrate incomplete dominance producing pink flowers. show the cross between a yellow and a pink flower- include the genotypes and phenotypes. can any of the offspring be yellow? explain.
in cats, blood-type A results from an allele (IA) that is dominant over an allele (iB) that produces blood-type B. There is no O blood type. The blood types of male and female cats that were mated and the blood types of their kittens follow. Give the most likely genotypes for the parents of each litter. Male parent Female parent Kittens 4 with type A, 3 with type B 6 with type B 8 with type A 7 with type A, 2 with type B 10 with type A 4 with type A, 1 with type B a. A в b. B B C. B A d. A A e. A A f. A B
The gene for flower color in snapdragons displays incomplete dominance. Snapdragons homozygous for the allele for red flower color have the genotype FRFR and have red flowers. Snapdragons homozygous for the allele for white flower color have the genotype FWFW and have white flowers. Heterozygous snapdragons, with the genotype FRFW, have pink flowers. A snapdragon that has pink flowers is crossed with a different snapdragon that has pink flowers. What percentage of the offspring is expected to have red, white, and pink flowers?
Labrador retrievers have 3 varieties of fur colour: yellow, chocolate or black. Two genes are involved, each with a dominant (Y and B) and a recessive allele (y and b). The allele Y codes for the ability to produce hair pigment: Yy and YY dogs have dark pigmented fur but all yy individuals are lighter coloured and yellow. The B allele codes for the ability to make hair with the darkest colouration: BB and Bb individuals have black fur; bb dogs have a lighter shade which is chocolate. In the blank Punnet Square below, calculate and state the ratio of phenotypes that occur with a cross between two individuals with the genotype YyBb.
Black coat colour in cocker Spaniels is governed by a dominant allele B and red coat colour by its recessive allele b; solid pattern is governed by the dominant allele of an independently assorting locus S, and sported pattern by its recessive allele s. A solid black male is mated to a solid red female and produces a litter of six pups: two solid black, two solid red, one black and white, and one red and white. (a) What are the possible genotypes of all the phenotypes obtainable? (b) Determine genotype of the parents. Hint- an unknown portion of a genotype may be indicated by a dash (-).
In some cats, the gene for tail length shows incomplete dominance. Cats homozygous for the long tail allele (T) have long tails and cats homozygous for the short tail allele (t) have no tails. Heterozygous cats have short tails. Draw a Punnett square for a mating between a short tail cat and a cat with no tail. According to your Punnett square, what is the percent chance that they would have a kitten with no tail? A)0% B)25% C)50% D)75% E)100%
Short hair in rabbit is controlled by T allele is dominant to long hair which is controlled by t allele. Black hair is controlled by B allele is dominant to brown hair which is controlled by b allele. A male rabbit has the genotype ttbb. If this rabbit mates with a female with genotype TtBb, determine the chances their offspring will have the genotype TtBb? * O 1/16 О 14 О 12 О 3/16
In cats, the allele (B) produces black color but (b) producesyellow color. These alleles are co‐dominant to each other. Aheterozygote produces a tortoise‐shell color. The alleles (B)and (b) are sex‐linked as well. Cross a tortoise‐shell femalewith a yellow male. What percent of their offspring will be yellow? What percent of their offspring will be black? What percent of their offspring will be tortoise shell?
In mice, there is an allele that in the heterozygous condition, produces mice with yellow coats. Mice that are homozygous recessive for the allele have white-color coats. Homozygous dominant mice abort early or are born stillborn. If a yellow male is mated to female yellow mouse, what is the phenotypic ratio you would expect among the 15 living offspring? (Show your work below.)