In cach of the ideal dıodes circuits below, v is a l KHz, SV peak since wave. Sketch the waveform resulting at vo. What are its positive and negative peak values? Dy D D; I kn Positive peak = negative peak = 1 k D, Z Positive peak - negative peak - 1 k2 O to Positive peak - negative peak =

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In each of the ideal diode circuits below, \(v_i\) is a 1 kHz, 5V peak sine wave. Sketch the waveform resulting at \(v_o\). What are its positive and negative peak values?

### Circuit 1:
- **Configuration:**
  - Input voltage \(v_i\) connected to a series combination of a resistor (1 kΩ) and three diodes (\(D_1\), \(D_2\), and \(D_3\)).
  - \(D_1\) is forward-biased with \(D_2\) and \(D_3\) arranged in series.
  - The output voltage \(v_o\) is taken across the parallel connection of the resistor and grounded diodes.
  
- **Graph:**
  - The graph shows \(v_o\) on the y-axis versus time \(t\) on the x-axis.
  - Positive and negative peaks are to be determined.

### Circuit 2:
- **Configuration:**
  - \(v_i\) is connected to a 1 kΩ resistor in series.
  - Two parallel diodes (\(D_1\) and \(D_2\)) are connected in reverse bias and grounded.
  - Output voltage \(v_o\) is measured across the series resistor.
  
- **Graph:**
  - Displays \(v_o\) versus time \(t\).
  - Positive and negative peaks are to be determined.

### Circuit 3:
- **Configuration:**
  - \(v_i\) passes through a 1 kΩ resistor.
  - A single diode \(D_1\) is forward-biased and connected to ground, creating a half-wave rectifier.
  - \(v_o\) is observed across the diode.
  
- **Graph:**
  - Illustrates \(v_o\) against \(t\).
  - Positive and negative peaks need to be defined.

### Circuit 4:
- **Configuration:**
  - \(v_i\) connected in series with a 1 kΩ resistor and \(D_1\).
  - Further, \(D_1\) is in series with a parallel combination of \(D_2\) (forward-biased) and a load resistor.
  - The output \(v_o\) is taken across the parallel branch.
  
- **Graph:**
  - Shows the relation of \(v_o\
Transcribed Image Text:In each of the ideal diode circuits below, \(v_i\) is a 1 kHz, 5V peak sine wave. Sketch the waveform resulting at \(v_o\). What are its positive and negative peak values? ### Circuit 1: - **Configuration:** - Input voltage \(v_i\) connected to a series combination of a resistor (1 kΩ) and three diodes (\(D_1\), \(D_2\), and \(D_3\)). - \(D_1\) is forward-biased with \(D_2\) and \(D_3\) arranged in series. - The output voltage \(v_o\) is taken across the parallel connection of the resistor and grounded diodes. - **Graph:** - The graph shows \(v_o\) on the y-axis versus time \(t\) on the x-axis. - Positive and negative peaks are to be determined. ### Circuit 2: - **Configuration:** - \(v_i\) is connected to a 1 kΩ resistor in series. - Two parallel diodes (\(D_1\) and \(D_2\)) are connected in reverse bias and grounded. - Output voltage \(v_o\) is measured across the series resistor. - **Graph:** - Displays \(v_o\) versus time \(t\). - Positive and negative peaks are to be determined. ### Circuit 3: - **Configuration:** - \(v_i\) passes through a 1 kΩ resistor. - A single diode \(D_1\) is forward-biased and connected to ground, creating a half-wave rectifier. - \(v_o\) is observed across the diode. - **Graph:** - Illustrates \(v_o\) against \(t\). - Positive and negative peaks need to be defined. ### Circuit 4: - **Configuration:** - \(v_i\) connected in series with a 1 kΩ resistor and \(D_1\). - Further, \(D_1\) is in series with a parallel combination of \(D_2\) (forward-biased) and a load resistor. - The output \(v_o\) is taken across the parallel branch. - **Graph:** - Shows the relation of \(v_o\
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