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In an oscillatory motion of a simple pendulum, the ratio of the maximum angular acceleration, O"max, to the maximum angular velocity, O'max, is 2t s^(-1). What is the time needed for the pendulum to complete two oscillations? O 4 sec O 1 sec 0.5 sec 2 sec 0.25 sec

In an oscillatory motion of a simple pendulum, the ratio of the maximum angular acceleration, O"max, to the maximum angular velocity, O'max, is 2t s^(-1). What is the time needed for the pendulum to complete two oscillations? O 4 sec O 1 sec 0.5 sec 2 sec 0.25 sec

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +4 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity +2 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple harmonic, which of the following is true? h2max = 9h1max and T2 = 3T, h2max = 4h, max and T = 27T, O Then we have O Then we have: h2max = hmax/4 and T = T, h2max = 9h, max and T2 = T, O Then we have: Then we have: h2max = 4h,max and T2 = T, search 立
Transcribed Image Text:A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +4 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and is given an initial velocity +2 m/s. The maximum height reached by the bob is h2,max and the period of motion is T2. Assume that the motion is simple harmonic, which of the following is true? h2max = 9h1max and T2 = 3T, h2max = 4h, max and T = 27T, O Then we have O Then we have: h2max = hmax/4 and T = T, h2max = 9h, max and T2 = T, O Then we have: Then we have: h2max = 4h,max and T2 = T, search 立
In an oscillatory motion of a simple pendulum, the ratio of the maximum angular acceleration, O"max, to the maximum angular velocity, O'max, is 2t s^(-1). What is the time needed for the pendulum to complete two oscillations? 4 sec 1 sec 0.5 sec 2 sec 0.25 sec A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +4 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and tu12 m/c The maxinmum height reached by the bob is
Transcribed Image Text:In an oscillatory motion of a simple pendulum, the ratio of the maximum angular acceleration, O"max, to the maximum angular velocity, O'max, is 2t s^(-1). What is the time needed for the pendulum to complete two oscillations? 4 sec 1 sec 0.5 sec 2 sec 0.25 sec A simple pendulum is set into motion at two different times with different initial conditions. The first time: the bob is in its equilibrium position and is given an initial velocity +4 m/s. The maximum height reached by the bob is h1,max and the period of motion is T1. The second time: the bob is in its equilibrium position and tu12 m/c The maxinmum height reached by the bob is
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