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In an open-circuit test of a 10KVA 2400/240V 60-cycle distribution transformer, the low side volts, amperes, and watts are found to be 240V, 0.75A and 72W. The low side, or secondary is short-circuited when 67V is applied to the high side, rated current of 4.17A flow in the power is 146W. Determine (i) equivalent impedance, referred to high and to low side; (ii) equivalent resistances; (iii) equivalent leakage reactance at rated load and unity power factor and at 0.80 power factor, lagging current, (iv) efficiency at rated kVA load; (v ) efficiency at 1/8, ½, 4, 5/4 kVA load. Plot efficiency as a function of kVA.

In an open-circuit test of a 10KVA 2400/240V 60-cycle distribution transformer, the low side volts, amperes, and watts are found to be 240V, 0.75A and 72W. The low side, or secondary is short-circuited when 67V is applied to the high side, rated current of 4.17A flow in the power is 146W. Determine (i) equivalent impedance, referred to high and to low side; (ii) equivalent resistances; (iii) equivalent leakage reactance at rated load and unity power factor and at 0.80 power factor, lagging current, (iv) efficiency at rated kVA load; (v ) efficiency at 1/8, ½, 4, 5/4 kVA load. Plot efficiency as a function of kVA.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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In an open-circuit test of a 10KVA 2400/240V 60-cycle distribution transformer, the low side volts, amperes, and watts are found to be 240V, 0.75A and 72W. The low side, or secondary is short-circuited when 67V is applied to the high side, rated current of 4.17A flow in the power is 146W. Determine (i) equivalent impedance, referred to high and to low side; (ii) equivalent resistances; (iii) equivalent leakage reactance at rated load and unity power factor and at 0.80 power factor, lagging current, (iv) efficiency at rated kVA load; (v ) efficiency at 1/8, V2, 4, 5/4 kVA load. Plot efficiency as a function of kVA.
Transcribed Image Text:In an open-circuit test of a 10KVA 2400/240V 60-cycle distribution transformer, the low side volts, amperes, and watts are found to be 240V, 0.75A and 72W. The low side, or secondary is short-circuited when 67V is applied to the high side, rated current of 4.17A flow in the power is 146W. Determine (i) equivalent impedance, referred to high and to low side; (ii) equivalent resistances; (iii) equivalent leakage reactance at rated load and unity power factor and at 0.80 power factor, lagging current, (iv) efficiency at rated kVA load; (v ) efficiency at 1/8, V2, 4, 5/4 kVA load. Plot efficiency as a function of kVA.
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