in an irrigation run, the infiltration rate (I) is constant and is equal to 20 mm/hr. The opportunity time at the inlet of the water run is 60 minutes. The infiltration depth at a distance :X, where the wetting front is located, is cm 4 .A cm 1 .B None of these options .C cm 2 .D

in an irrigation run, the infiltration rate (I) is constant and is equal to 20 mm/hr. The opportunity time at the inlet of the water run is 60 minutes. The infiltration depth at a distance :X, where the wetting front is located, is cm 4 .A cm 1 .B None of these options .C cm 2 .D

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

6) The modified Blaney-Criddle Formula is used to estimate infiltration capacity for arid and semi-arid regions. * False True
For a certain catchment with an area of 1000000m2, the average precipitation was 7cm and infiltration was 4cm. The hydrograph values are 20, 60, 88, 105, 70, 57, 20, and 5 m3/s and the base flow has constant value of 10 m3/s, the peak unit hydrograph ordinate is equal to
Complete solution please
Q3. It was rained on a basin, where the soil has a k constant of 1.7, an initial infiltration rate of 3.2 mm/hr, and an infiltration rate of 2.3 mm/hr minutes later. The precipitation depths versus time are tabulated below: t, hr 600 615 630 645 700 715 730 745 800 815 80 845 900 915 | ΣΡ, cm 0.0 0.4 2.0 3.8 5.0 5.0 5.0 UH, (m/s)/cm o 10 35 65 85 75 50 35 25 18 12 6. 2 a) Obtain Horton's infiltration equation (10 points), b) Calculate the depth of total infiltrated water, the depth of surface runoff, and the runoff coefficient (20 points), c) 30-minute unit hydrograph (UH) ordinates are also tabulated above. Obtaining 15-minute UH and neglecting the losses except for the infiltration, determine the direct runoff hydrograph. (30 point).
Paragraph Problem 1: A pipe is laid horizontally and filled with soil, with its open end being saturated. With the given data, solve for its infiltration in 36mins if the soil column had been initially placed upright with its upper surface saturated. Area of the pipe's cross section = 212.6cm2 Infiltrated by 2126cm? of water after 26mins Hydraulic conductivity is 0.001cm/s (Final answer should be in 4 decimal places.) Problem 2: With the given data, solve for the infiltration rate and cumulative infiltration after 360mins on a sandy clay soil. Assume water is ponded to a small but negligible depth on the surface. Moisture Content of the soil = 34.5% Residual Moisture Content of the soil = 26% (Final answers should be in 4 decimal places.) The table will be provided in page 2 Problem 3: Using the data from Problem 2. What is its ponding time if: a) Intensity of rainfall is 0.000126cm/s. b) Intensity of rainfall is 5.8344cm/d. (Final answers should be in 4 decimal places.) Problem 4:…
IQ4// [A]: For a small drainage area, the infiltration rate at the start of rainfall storm was record to be 90 mm/hr and declined exponentially to a constant rate of 8 mm/hr after 2.5 hr. The total infiltration during 2.5 hr was 50 mm. Develop the Horton's equation for the infiltration rate at any time t<2.5 hr. [B]: Find the required discharge of irrigation water at the headwork of the distiriburatry, if the gross area is 20000 mishara, the irrigation intensity is 65%, and the water duty is 1600 hectare/m/sec.
A pump can lift water at a discharge of 0.15 m³/s to a head of 25 m. The critical cavitation number (o) for the pump is found to be 0.144. The pump is to be installed at a location where the barometric pressure is 9.8 m of water and the vapour pressure of water is 0.30 m of water. The intake pipe friction loss is 0.40 m. Using the minimum value of NPSH (Net Positive Suction Head), the maximum allowable elevation above the sump water surface at which the pump can be located is
Given the earth dam and flow net shown, calculate the seepage loss under the dam if the water height behind the dam is 15ft. The soil has a hydraulic conductivity of 100 ft/year. EL 0 EL-10 Water Level 730 ft³/year O 650 ft³/year 500 ft³/year 890 ft³/year Water Level Yail=130 lb/ft³ Impervious Stratum
A pump can lift water at a discharge of 0.15m³/s to a head of 25 m. The critical cavitation number (c) for the pump is found to be 0.144. The pump is to be installed at a location where the barometric pressure is 9.8 m of water and the vapour pressure of water is 0.30 of water. The intake pipe friction loss is 0.40 m. Using the minimum value of NPSH (Net Positive Suction Head), the maximum allowable elevation above the sump water surface at which the pump can be located is
Figure Q1(d) shows a layer of soil in a tank with upward seepage. Given the H1 = 1.5 m, H2 =2.5 m, h = 1.5 m, ysat = 18.6 kN/m³. If the hydraulic conductivity of soil, k = 0.13 cm/s; (i) Compute the upward seepage force per unit volume of soil. (ii) Determine the rate of upward seepage of water if the area of tank is 0.52 m? in m³ /min.