In an amusement fair, a competitor is entitled for a prize if he throws a ring on a from a certain distance. It is observed that only 30% of the competitors can do this. If someone is given 5 chances, what is the probability of his winning the prize when he has already missed 4 chances?

A First Course in Probability (10th Edition)
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Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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Determine the expected number and variance of winning in problem

GEOMETRIC DISTRIBUTION
In an amusement fair, a competitor is entitled for a prize if he throws a ring on a peg
from a certain distance. It is observed that only 30% of the competitors can do
this. If someone is given 5 chances, what is the probability of his winning the prize
when he has already missed 4 chances?
Solution:
g (x; p) = p(q)*-1
%3D
X = 5 (total chances)
r = 1 (success at last chance)
f(x = 5) = 0.30(0.70)5-1
%3D
f(x = 5) = 0. 07203
p = 0.30 (succes5)
q = 0.70
Chance of winning at last chance is
7.203%
ILLUSTRATIVE PROBLEM #4
Transcribed Image Text:GEOMETRIC DISTRIBUTION In an amusement fair, a competitor is entitled for a prize if he throws a ring on a peg from a certain distance. It is observed that only 30% of the competitors can do this. If someone is given 5 chances, what is the probability of his winning the prize when he has already missed 4 chances? Solution: g (x; p) = p(q)*-1 %3D X = 5 (total chances) r = 1 (success at last chance) f(x = 5) = 0.30(0.70)5-1 %3D f(x = 5) = 0. 07203 p = 0.30 (succes5) q = 0.70 Chance of winning at last chance is 7.203% ILLUSTRATIVE PROBLEM #4
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