In an agricultural experiment, the effects of two fertilizers on the production of limes were measured. Twenty-three randomly selected plots of land were treated with a brand new fertilizer, and 21 randomly selected plots were treated with an old fertlizer. The number of pounds of harvested limes were measured from each plot. The results are given below. (Round answers to two decimal places.)Data:New FertilizerOld Fertilizer412480434472436485418453412470415464412482438466439481443470427472426466439493427471438495430479411467424476419493424485425482437 420Find a 90% confidence interval for the difference between the mean weight of the harvested limes.margin of error: lower limit: upper limit: Based on the results, is the new fertilizer better than the old fertilizer?Yes, we are 90% confident that new fertilizer is better than old fertilizer.It's not clear if the new fertilizer is better than the old fertilizer.No, we are 90% confident that new fertilizer is not better than old fertilizer.

Given data, New Fertilizer Old Fertilizer 412 480 434 472 436 485 418…

Answered: In an agricultural experiment, the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In an agricultural experiment, the effects of two fertilizers on the production of limes were measured. Twenty-three randomly selected plots of land were treated with a brand new fertilizer, and 21 randomly selected plots were treated with an old fertlizer. The number of pounds of harvested limes were measured from each plot. The results are given below. (Round answers to two decimal places.)

Data:

New Fertilizer	Old Fertilizer
412	480
434	472
436	485
418	453
412	470
415	464
412	482
438	466
439	481
443	470
427	472
426	466
439	493
427	471
438	495
430	479
411	467
424	476
419	493
424	485
425	482
437
420

Find a 90% confidence interval for the difference between the mean weight of the harvested limes.

margin of error:
lower limit:
upper limit:

Based on the results, is the new fertilizer better than the old fertilizer?

Yes, we are 90% confident that new fertilizer is better than old fertilizer.
It's not clear if the new fertilizer is better than the old fertilizer.
No, we are 90% confident that new fertilizer is not better than old fertilizer.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Expert Solution

Step 1

Given data,

New Fertilizer	Old Fertilizer
412	480
434	472
436	485
418	453
412	470
415	464
412	482
438	466
439	481
443	470
427	472
426	466
439	493
427	471
438	495
430	479
411	467
424	476
419	493
424	485
425	482
437
420

Mean and standard deviation:

Mean of new fertilizer is 426.35 ( obtained using “=AVERAGE(A1:A23)”.

Mean of old fertilizer is 476.29 ( obtained using “=AVERAGE(B1:B21)”.

Standard deviation of new fertilizer is 10.24 ( obtained using “=STDEV.S(A1:A23)”.

Standard deviation of old fertilizer is 10.73 ( obtained using “=STDEV.S(A1:A21)”.

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