In acidic aqueous solution, the purple complex ion Co(NH3)5Br2+Co(NH3)5Br2+ undergoes a slow reaction in which the bromide ion is replaced by a water molecule, yielding the pinkish-orange complex ion : Co(NH3)5(H2O)3+Co(NH3)5(H2O)3+ Co(NH3)5Br2+Purple(aq)+H2O(l)→Co(NH3)5Br2+Purple(��)+H2O(�)→ Co(NH3)5(H2O)3+Pinkish−orange(aq)+Br−(aq)Co(NH3)5(H2O)3+Pinkish−orange(��)+Br−(��) The reaction is first order
In acidic aqueous solution, the purple complex ion Co(NH3)5Br2+Co(NH3)5Br2+ undergoes a slow reaction in which the bromide ion is replaced by a water molecule, yielding the pinkish-orange complex ion : Co(NH3)5(H2O)3+Co(NH3)5(H2O)3+ Co(NH3)5Br2+Purple(aq)+H2O(l)→Co(NH3)5Br2+Purple(��)+H2O(�)→ Co(NH3)5(H2O)3+Pinkish−orange(aq)+Br−(aq)Co(NH3)5(H2O)3+Pinkish−orange(��)+Br−(��) The reaction is first order
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In acidic aqueous solution, the purple complex ion Co(NH3)5Br2+Co(NH3)5Br2+ undergoes a slow reaction in which the bromide ion is replaced by a water molecule, yielding the pinkish-orange complex ion : Co(NH3)5(H2O)3+Co(NH3)5(H2O)3+
Co(NH3)5Br2+Purple(aq)+H2O(l)→Co(NH3)5Br2+Purple(��)+H2O(�)→ Co(NH3)5(H2O)3+Pinkish−orange(aq)+Br−(aq)Co(NH3)5(H2O)3+Pinkish−orange(��)+Br−(��)
The reaction is first order in Co(NH3)5Br2+Co(NH3)5Br2+, the rate constant at 25 ∘C∘C is 6.3×10−66.3×10−6 s−1s−1, and the initial concentration of Co(NH3)5Br2+Co(NH3)5Br2+ is 0.100 MM.
What is its molarity after a reaction time of 15.0 hh ?
Express your answer using two significant figures.
How many hours are required for 77 %% of the Co(NH3)5Br2+Co(NH3)5Br2+ to react?
Express your answer using two significant figures.
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