In ACDE, the measure of E=90°, the measure of ZC=83°, and DE = 8.6 feet. Find the length of EC to the nearest tenth of a foot. D 8.6 830 C E X.

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Q: E 40 190 F

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A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

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A: Given:    To  find: AC

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A: we know angle of semicircle is 90°therefore∠LEM=90°

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