In a "worst-case" design scenario, a 2000 kg elevator with broken cables is falling at 4.00 m/s when it first contacts a cushioning spring at the bottom of the shaft. The spring is supposed to stop the elevator, compressing 2.00 m as it does so. Spring coefficient is 10.6 kN/m. During the motion a safety clamp applies a constant 17000-N frictional force to the elevator. • Part A What is the speed of the elevator after it has moved downward 1.00 m from the point where it first contacts a spring? Express your answer in meters per second. ν ΑΣφ ? v = m/s Submit Request Answer
In a "worst-case" design scenario, a 2000 kg elevator with broken cables is falling at 4.00 m/s when it first contacts a cushioning spring at the bottom of the shaft. The spring is supposed to stop the elevator, compressing 2.00 m as it does so. Spring coefficient is 10.6 kN/m. During the motion a safety clamp applies a constant 17000-N frictional force to the elevator. • Part A What is the speed of the elevator after it has moved downward 1.00 m from the point where it first contacts a spring? Express your answer in meters per second. ν ΑΣφ ? v = m/s Submit Request Answer
Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter7: Energy Of A System
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What's the answer for part A and B?
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>
Constants
In a "worst-case" design scenario, a 2000 kg elevator with broken cables is falling
at 4.00 m/s when it first contacts a cushioning spring at the bottom of the shaft.
The spring is supposed to stop the elevator, compressing 2.00 m as it does so.
Spring coefficient is 10.6 kN/m. During the motion a safety clamp applies a
constant 17000-N frictional force to the elevator.
Part A
What is the speed of the elevator after it has moved downward 1.00 m from the
point where it fırst contacts a spring?
Express your answer in meters per second.
ΑΣΦ
?
V =
m/s
Submit
Request Answer
Part B
When the elevator is 1.00 m below point where it first contacts a spring, what is
its acceleration?
Express your answer in meters per square second.
?
a =
m/s?
Submit
Request Answer"
Transcribed Image Text:19 of 32
>
Constants
In a "worst-case" design scenario, a 2000 kg elevator with broken cables is falling
at 4.00 m/s when it first contacts a cushioning spring at the bottom of the shaft.
The spring is supposed to stop the elevator, compressing 2.00 m as it does so.
Spring coefficient is 10.6 kN/m. During the motion a safety clamp applies a
constant 17000-N frictional force to the elevator.
Part A
What is the speed of the elevator after it has moved downward 1.00 m from the
point where it fırst contacts a spring?
Express your answer in meters per second.
ΑΣΦ
?
V =
m/s
Submit
Request Answer
Part B
When the elevator is 1.00 m below point where it first contacts a spring, what is
its acceleration?
Express your answer in meters per square second.
?
a =
m/s?
Submit
Request Answer
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