In a voltaic cell, there exists a Fe/Fe2+ half-cell and a Sn/Sn2+ half-cell at a temperature of 25°C. The initial concentrations of Sn2* and Fe2+ are 5.26 mol L-1 and 0.176 mol L-1, respectively. Fe2+(aq) + 2e → Fe(s) E° = -0.45 V Sn2(aq) + 2e → Sn(s) E° = -0.14 V What are the concentrations of Sn2* and Fe2+ when the cell potential decreases to 0.26 V?
In a voltaic cell, there exists a Fe/Fe2+ half-cell and a Sn/Sn2+ half-cell at a temperature of 25°C. The initial concentrations of Sn2* and Fe2+ are 5.26 mol L-1 and 0.176 mol L-1, respectively. Fe2+(aq) + 2e → Fe(s) E° = -0.45 V Sn2(aq) + 2e → Sn(s) E° = -0.14 V What are the concentrations of Sn2* and Fe2+ when the cell potential decreases to 0.26 V?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Step 1: Defining Voltaic cell!
VIEWStep 2: Finding out the standard cell potential!
VIEWStep 3: Finding out relation between concentration of both the ions when cell potential decreases to 0.26V
VIEWStep 4: Formation of BCA table!
VIEWStep 5: Finding out the value of unknown y
VIEWStep 6: Finding out the concentration of both the ions when cell potential decreases to 0.26V!
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