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For Questions 20-24 consider the following scenario: A 0.8390 g of an unknown sample containing chloride was dissolved in water and reacted with an excess of AgNO3 solution. The following data was collected from the gravimetric analysis: Mass of Unknown Sample = 0.8390 g Mass of Filter Paper and Precipitate = 3.2174 g Mass of Filter Paper =1.0230 g It was determined in the previous questions that 2.1944 g of AgCl precipitated. Calculate the moles of the precipitate

For Questions 20-24 consider the following scenario: A 0.8390 g of an unknown sample containing chloride was dissolved in water and reacted with an excess of AgNO3 solution. The following data was collected from the gravimetric analysis: Mass of Unknown Sample = 0.8390 g Mass of Filter Paper and Precipitate = 3.2174 g Mass of Filter Paper =1.0230 g It was determined in the previous questions that 2.1944 g of AgCl precipitated. Calculate the moles of the precipitate

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For Questions 20-24 consider the following scenario: A 0.8390 g of an unknown sample containing chloride was dissolved in water and reacted with an excess of AGNO, solution. The following data was collected from the gravimětric analysis: Mass of Unknown Sample = 0.8390 g Mass of Filter Paper and Precipitate = 3.2174 g Mass of Filter Paper =1.0230 g It was determined in the previous questions that 2.1944 g of AgCl precipitated. Calculate the moles of the precipitate
Transcribed Image Text:For Questions 20-24 consider the following scenario: A 0.8390 g of an unknown sample containing chloride was dissolved in water and reacted with an excess of AGNO, solution. The following data was collected from the gravimětric analysis: Mass of Unknown Sample = 0.8390 g Mass of Filter Paper and Precipitate = 3.2174 g Mass of Filter Paper =1.0230 g It was determined in the previous questions that 2.1944 g of AgCl precipitated. Calculate the moles of the precipitate
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