- in a two-layer uniform changing field electrode system separated by the boundary plane x=0, the electric field in the first layer the amplitude of its vector is 80kV/cm, the angle it makes with the perpendicular component is 20°. The relative dielectric constants of the layers are 4 and respectively 2. calculate the tangent component of the electric field in the second layer. O 22 kV/ cm O 19 kV/ cmi 01106 27 kV/ cm 1 O 29 kV / cmi O 18 kV/ cm

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- in a two-layer uniform changing field electrode system separated by the boundary plane x=0, the electric field in the first layer the amplitude of
its vector is 80kV/cm, the angle it makes with the perpendicular component is 20°. The relative dielectric constants of the layers are 4 and
respectively 2. calculate the tangent component of the electric field in the second layer.
O 22 kV/ cm
O 19 kV/ cmi
01106
O 27 kV / cm 1
O 29 kV / cmi
O 18 kV/ cm
Transcribed Image Text:- in a two-layer uniform changing field electrode system separated by the boundary plane x=0, the electric field in the first layer the amplitude of its vector is 80kV/cm, the angle it makes with the perpendicular component is 20°. The relative dielectric constants of the layers are 4 and respectively 2. calculate the tangent component of the electric field in the second layer. O 22 kV/ cm O 19 kV/ cmi 01106 O 27 kV / cm 1 O 29 kV / cmi O 18 kV/ cm
Expert Solution
Step 1

We will boundary conditions to find tangential component of electric field.

Tangential component of electric field intensity is same at boundary.

normal component of electric flux density is same at boundary. 

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