In a three-digit lottery, each of the three digits is supposed to have the same probability of occurrence (counting initial blanks as zeros. e.g., 32 is treated as 032). The table shows the frequency of occurrence of each digit for 90 consecutive daily three-digit drawings. Digit 1 2 3 4 5 6 7 8 9 Total Frequency 18 15 26 30 30 21 30 34 35 31 270 picture Click here for the Excel Data File (0) Calculate the chi-square test statistic, degrees of freedom, and the p-value. (Perform a uniform goodness-of-fit test. Round your test statistic value to 2 decimal places and the p-value to 4 decimal places.) Test statistic Degrees of freedom p-value

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In a three-digit lottery, each of the three digits is supposed to have the same probability of occurrence (counting initial blanks as zeros.
e.g., 32 is treated as 032). The table shows the frequency of occurrence of each digit for 90 consecutive daily three-digit drawings.
Digit
1
2
3
4
5
6
7
8
9
Total
Frequency
18
15
26
30
30
21
30
34
35
31
278
picture Click here for the Excel Data File
(a) Calculate the chi-square test statistic, degrees of freedom, and the p-value. (Perform a uniform goodness-of-fit test. Round your
test statistic value to 2 decimal places and the p-value to 4 decimal places.)
Test statistic
Degrees of freedom
p-value
(b) Choose the correct answer by drawing a bar chart for the above data.
O The graph will reveal that 1 occurs least frequently.
O The graph will reveal that 2 occurs least frequently.
O The graph will reveal that 8 occurs least frequently.
O The graph will reveal that 9 occurs least frequently.
(c) At a = .01, we cannot reject the hypothesis that the digits are from a uniform population.
O True
O False
Transcribed Image Text:In a three-digit lottery, each of the three digits is supposed to have the same probability of occurrence (counting initial blanks as zeros. e.g., 32 is treated as 032). The table shows the frequency of occurrence of each digit for 90 consecutive daily three-digit drawings. Digit 1 2 3 4 5 6 7 8 9 Total Frequency 18 15 26 30 30 21 30 34 35 31 278 picture Click here for the Excel Data File (a) Calculate the chi-square test statistic, degrees of freedom, and the p-value. (Perform a uniform goodness-of-fit test. Round your test statistic value to 2 decimal places and the p-value to 4 decimal places.) Test statistic Degrees of freedom p-value (b) Choose the correct answer by drawing a bar chart for the above data. O The graph will reveal that 1 occurs least frequently. O The graph will reveal that 2 occurs least frequently. O The graph will reveal that 8 occurs least frequently. O The graph will reveal that 9 occurs least frequently. (c) At a = .01, we cannot reject the hypothesis that the digits are from a uniform population. O True O False
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