Plot and describe the distribution of breakup dates, and provide appropriaate numerical summaries. Which statement describes the distribution of breakup dates? The histogram indicates the distribution of breakup dates is right-skewed. The histogram indicates the distribution of breakup dates is left-skewed. The histogram indicates the distribution of breakup dates is roughly symmetric. The histogram indicates the distribution of breakup dates has no obvious skew and is not symmetric. Provide the mean of breakup dates. Give your answer to one decimal place. mean: Provide the standard deviation of breakup dates. Give your answer to two decimal places. standard deviation: days days

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Macmillan Learning
Plot and describe the distribution of breakup dates, and provide appropriaate numerical summaries.
Which statement describes the distribution of breakup dates?
The histogram indicates the distribution of breakup dates is right-skewed.
The histogram indicates the distribution of breakup dates is left-skewed.
The histogram indicates the distribution of breakup dates is roughly symmetric.
The histogram indicates the distribution of breakup dates has no obvious skew and is not symmetric.
Provide the mean of breakup dates. Give your answer to one decimal place.
mean:
Provide the standard deviation of breakup dates. Give your answer to two decimal places.
standard deviation:
day's
days
Transcribed Image Text:Macmillan Learning Plot and describe the distribution of breakup dates, and provide appropriaate numerical summaries. Which statement describes the distribution of breakup dates? The histogram indicates the distribution of breakup dates is right-skewed. The histogram indicates the distribution of breakup dates is left-skewed. The histogram indicates the distribution of breakup dates is roughly symmetric. The histogram indicates the distribution of breakup dates has no obvious skew and is not symmetric. Provide the mean of breakup dates. Give your answer to one decimal place. mean: Provide the standard deviation of breakup dates. Give your answer to two decimal places. standard deviation: day's days
The Nenana Ice Classic is an annual contest to guess the exact time in the spring thaw when a tripod erected on the frozen.
Tanana River near Nenana, Alaska, will fall through the ice. The contest has been run since 1917. The 2017 jackpot was
$267,444. The table gives simplified data that record only the date on which the tripod fell each year. The earliest date so far
is April 20. To make the data casier to use, the table gives the date each year in days starting with April 20. That is, April 20
is 1, April 21 is 2, and so on.
Days from April 20 for the
Tanana River tripod to fall
Duy
Year
1917
1918
1919
1920
1921
1922
1923
1924
1925
1926
1927
1928
1929
1930
1931
1932
1933
Year
1948
1969
1970
1971
1972
1973
1974
1975
1976
1977
1978
1979
1980
1981
1982
Days from April 20 for the
Tanana River tripod to fall
1983
11
1984
22
14
22
22
23
20
22
16
7
23
17
16
19
21
12
19
Day
19
9
15
19
21
15
17
21
17
11.
11
10
11
21
10
20
Days from April 20 for the
Tanana River tripod to fall
Year
1934
1935
1936
1937
1938
1939
1940
1941
1942
1943
1944
1945
1946
1947
1948
1949
1950
Year
1985
1986
1987
1988
1989
1990
1991
1992
1993
1994
1995
1996
1997
1998
1999
2000
Days from April 20 for the
Tanana River tripod to fall
2001
Day
.
11
26
11
23
17
10
1
14
11
9
15
27
16
14
24
25
17
Day
23
19
16
8
12
$
12
25
4
10
1
16
11
I
36
12
19
Days from April 20 for the
Tanana River tripod to fall
Day
Year
1951
1952
1953
1954
1955
1956
1957
1958
1959
1960
1961
1962
1963
1964
1965
1966
1967
Year
2002
2003
2004
2005
2006
2007
2008
2009
2010
2011
2012
2013
2014
2015
2016
11
Days from April 20 for the
Tanana River tripod to fall
Day
2017
23
10
17
20
12
16
10
19
13
16
23
16
31
IN
19
15
18
10
S
4
13
8
17
12
10
15
4
31
6
3
4
12
Transcribed Image Text:The Nenana Ice Classic is an annual contest to guess the exact time in the spring thaw when a tripod erected on the frozen. Tanana River near Nenana, Alaska, will fall through the ice. The contest has been run since 1917. The 2017 jackpot was $267,444. The table gives simplified data that record only the date on which the tripod fell each year. The earliest date so far is April 20. To make the data casier to use, the table gives the date each year in days starting with April 20. That is, April 20 is 1, April 21 is 2, and so on. Days from April 20 for the Tanana River tripod to fall Duy Year 1917 1918 1919 1920 1921 1922 1923 1924 1925 1926 1927 1928 1929 1930 1931 1932 1933 Year 1948 1969 1970 1971 1972 1973 1974 1975 1976 1977 1978 1979 1980 1981 1982 Days from April 20 for the Tanana River tripod to fall 1983 11 1984 22 14 22 22 23 20 22 16 7 23 17 16 19 21 12 19 Day 19 9 15 19 21 15 17 21 17 11. 11 10 11 21 10 20 Days from April 20 for the Tanana River tripod to fall Year 1934 1935 1936 1937 1938 1939 1940 1941 1942 1943 1944 1945 1946 1947 1948 1949 1950 Year 1985 1986 1987 1988 1989 1990 1991 1992 1993 1994 1995 1996 1997 1998 1999 2000 Days from April 20 for the Tanana River tripod to fall 2001 Day . 11 26 11 23 17 10 1 14 11 9 15 27 16 14 24 25 17 Day 23 19 16 8 12 $ 12 25 4 10 1 16 11 I 36 12 19 Days from April 20 for the Tanana River tripod to fall Day Year 1951 1952 1953 1954 1955 1956 1957 1958 1959 1960 1961 1962 1963 1964 1965 1966 1967 Year 2002 2003 2004 2005 2006 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 11 Days from April 20 for the Tanana River tripod to fall Day 2017 23 10 17 20 12 16 10 19 13 16 23 16 31 IN 19 15 18 10 S 4 13 8 17 12 10 15 4 31 6 3 4 12
Expert Solution
Step 1

Data is given for 1917 to 2017 

Days : 

11,22,14,22,23,20.....31,6,3,4,12 

We have to creat histogram.

We have to calculate mean and standard deviation for mentioned data.

 

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