In a test run, a certain car accelerates uniformly from zero to 19.8 m/s in 2.50 s. (a) What is the magnitude of the car's acceleration? m/s2 (b) How long does it take the car to change its speed from 9.90 m/s to 19.8 m/s? (c) Will doubling the time always double the change in speed? Yes O No Why?
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
![In a test run, a certain car accelerates uniformly from zero to 19.8 m/s in 2.50 s.
(a) What is the magnitude of the car's acceleration?
m/s2
(b) How long does it take the car to change its speed from 9.90 m/s to 19.8 m/s?
(c) Will doubling the time always double the change in speed?
O Yes
O No
Why?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4889a1b2-cd02-493f-a3b5-7c3cbfe1f622%2F3facb9f6-f7fe-4a09-a519-3ee54a66f203%2F3fpa8cp_processed.jpeg&w=3840&q=75)
![](/static/compass_v2/shared-icons/check-mark.png)
Given:
Initial velocity , u = 0
Final velocity, v = 19.8 m/s
Time , t = 2.50 s
To determine:
(a) the magnitude of the car's uniform acceleration.
(b) time taken by the car to change its speed from 9.90 m/s to 19.8 m/s
( c ) Will doubling the time always double the change in speed.
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