The displacement and the corresponding time of a moving body at constant acceleration is recorded as follows: Time (s) Displacement (m) From these data, what is the average acceleration of the motion? O 5.5 m/s² O 6.9 m/s² 1 3 2 13.2 O-2.2 m/s² O It is not moving at constant acceleration. 3 21.2 4 27 5 30.6
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- Which graph best represents a positive acceleration?v (m/s) velocity 10 30 (a) Walking velocity of Tom v (m/s) 20 velocity 10 t (sec) time 30 15 (a) Walking velocity of Susan t (sec) time The walking distance is velocity x time, if the velocity is constant. If the velocity changes, the walking distance is the area under the time-velocity plot. What is the walking distance of Tom and Susan?3. Shown below is the acceleration function for a particle over the approximately first two seconds of its motion. Draw an approximate graph of velocity as a function of time assuming v, = 0 m/s. alt) t 20 15 10 5. 0.5 1.0 1.5 2.0 2.5 4. Let vector A point from the origin into the first quadrant of the xy plane and vector B point from the origin into the third quadrant. The vector Ă – B must be in which quadrant?
- 1. A train leaves the station on a 50 km commute. The train must make a 60-second stopevery 1.0 km to pick up and drop off passengers. The train accelerates at 2.0 m/s2, then cruises at90 km/h, and then decelerates at 5.0 m/s2 between stops.(a.} How many stops does the train make?(b.} How long does it take for the train to get from one stop to the next?(c.} What is the total time for the entire commute?The velocity vs. time graph for an object in motion is shown below. What is the total distance traveled by the object? velocity vs time 2.5 2 1.5 1 0.5 1 2 4 5 -0.5 -1 -1.5 time (s) 16 m 4 m 8 m 2 m 3. velocity (m/s) O O O6 5 1 2 3 4 5 6 8 Time (s) The graph represents the relationship between distance and time for an object that is moving along a straight line. What is the instantaneous speed of the object at t = 5.0 seconds? 0.8 m/s O 0.0 m/s 2.5 m/s O 4.0 m/s 4. 3. Distance (m)
- Let's look at Figure 3, which is another position vs time graph. Figure 3 10 C 8 4 2 0.00 0.25 0.50 0.75 1.00 1.25 1.50 1.75 2.00 Time (s) We have labelled 3 points. They occur at zero, one, and two seconds. The slopes have been indicated by a red line. What can we learn from this? If we look at slope A, we can tell that the velocity is zero at this point because the slope line is horizontal. A horizontal slope is zero because the change in the vertical direction is zero. Slope B is a positive slope since it points upward. Another way to say it is that it is rotated counter-clockwise from the horizontal. Slope C is the largest of the three slopes. Therefore, we can say that the velocity of the object increases from zero to some positive value. We know that the velocity is changing in the positive direction. This means that the acceleration of the object must be positive. Homework: Consider the position vs time graph in Figure 3. a) Sketch (estimate) an appropriate corresponding…QUESTION 15 Velocity vs. Time 一 :B : 15 10 4 6. Time (seconds) > 8. 10 What is the average velocity for the time segment A on the Velocity vs. Time Graph? 5 m/s O 10 m/s 20 m/s 台 |期 樂 . ... I2. .... .. E . .. ... .... ... 5 2 5 Velocity (m/s)An equation describing displacement (in meters) as a function of time (in seconds) of a rocket propelled motorcycle moving up a hill is given by: x(t) = 13.5t – 0.5t³ + 7 Where 03.5 3 2.5 2 1.5 1 0.5 0 0 0.5 1 1.5 2 2.5 3 3.5 4 t(s) The plot shows the positions of two cars A (the red line) and B (the blue line). At what time is the velocity of A and B the same? They never have the same velocity. O 2.50 s O 1.67 s O 3.33 s9 ΔΔΔ Δ Δ ΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΔΑ What is the approximate total displacement based on the graph below? use 2 sfs. Approximate the values on each axis to the best of your ability. 560 (velocity mis 50 2240 30 P 10 123 I 3 4 5 Time (s) 1 678 9 2Help, pleaseSEE MORE QUESTIONS