In a test of Ho: µ = 100 against Ha: µ 100, a sample of size 80 produces z = 0.8 for the value of the test statistic. The P-value of the test is thus equal to:
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100, a sample of size 80 produces z = 0.8 for the
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- In a test of h0 u=100 against ha :u>100 the sample data yielded the test statistic z=2.17 find and interpret the p-valueA survey is conducted to determine if there is a difference in the proportion of students, parents, and The conditions for inference are met. The chi-square test statistic is 0.19 and df = 2. What is the appropriate decision using a = 0.05? teachers who volunteer at least once a month. To investigate, a random sample of 45 students, 25 parents, and 12 teachers was selected from a large high school. The data are displayed in the table. Find the chi-square table here. Because the P-value is less than a = 0.05, the null hypothesis should be rejected. Student Parent Teacher Because the P-value is less than a = 0.05, the null hypothesis should not be rejected. Yes 24 12 Volunteer? No 21 13 Because the P-value is greater than a = 0.05, the null hypothesis should be rejected. The researcher would like to test these hypotheses: Because the P-value is greater than a = 0.05, the null hypothesis should not be rejected. Họ: There is no difference in the distribution of responses among these three…21 smooth/yellow 42 smooth/light-yellow 19 smooth/white 22 wrinkled/yellow 39 wrinkled/light-yellow 20 wrinkled/white Calculate the Chi Sqaure statistic of the data shown above:
- When creating a 99% CI based on data from one sample the size of n=31, which t value should be used?A pet food company is concerned that their pet food must have a certain % of the mineral zinc in the food. Too little and dogs get very sick. If the machinery is working correctly, the average zinc is u = .375 gram/lb of food. They sample 25 bags of food and find: i = .359 grams o = .05 grams The firm wants to know if their pet food is healthy. They decide on a 95% level of significance. Do the Z test. They ask you to perform the analysis. a) State the null and alternative hypotheses. Ho: На: b) Draw a picture/graph of what you are trying to find. c) Find the critical value you will use. d) Compute the test statistic (from the data) e) What do you conclude? Why?The results of a one sample t test are reported as follows: T(15) = 1.70, p>.01. Based on these results were the results statistically signifigant?
- 6/10It is of interest to determine if the average drying time of a certain brand of latex paint is not 4.5 hours. To do this, 15 cans of the branded latex paint were selected. Normality test of drying time of the branded latex paint: Shapiro-Wilk normality test data: drying time W = 0.9691, p-value = 0.1396 Which of the following is the most appropriate test to use to determine if the average drying time of a certain brand of latex paint is not 4.5 hours? Choices: A. Approximate Z-test on one population proportion B. Wilcoxon signed-rank test C. t-test on one population mean D. Chi-square test on varianceCreate your own sample size and mean
- In the ANOVA results table for a 2° experiment, the P-value for the sample F-ratio of interaction AB is equal to 0.0245. The interaction AB is statistically significant at a-0.05. Select one: O True O Falseassume that the data was obtained from two indepen-dent samples. That is, 28 subjects were enrolled into the study, and half were randomly assignedto the corn flakes diet, and half to the oat bran diet. After two weeks the LDL cholesterol level ofeach individual was recorded. LDL (mmol/l)Subject Corn Flakes Oat Bran1 4.61 3.842 6.42 5.573 5.40 5.854 4.54 4.805 3.98 3.686 3.82 2.967 5.01 4.418 4.34 3.729 3.80 3.4910 4.56 3.8411 5.35 5.2612 3.89 3.7313 2.25 1.8414 4.24 4.14 Questions; a) What are the appropriate null and alternative hypotheses for a two-sided test?(b) Conduct the test at the 0.05 level of significance. What is the p-value?(c) Construct a 95% confidence interval.The claim is that for a smartphone carriers data speeds at airports, the mean is u= 12.00 Mbps. The sample size is n=11 and the test statistic is t=1.415.
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