In a test of Ho: µ = 100 against Ha: µ 100, a sample of size 80 produces z = 0.8 for the value of the test statistic. The P-value of the test is thus equal to:
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A: The following information is available in the question Effect size=0.47μ1-μ2=0n1=75n2=125
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A: HERE GIVEN n1=25, n2=30 X1¯=20, X2¯=18 S1=1.5, S2= 1.9
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A: n=10=8.7s=1.3=0.05
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- One group of accounting students took a distance learning class, while another group took the same course in a traditional classroom. At α = .10, is there a significant difference in the mean scores listed below? Exam Scores for Accounting Students Statistic Distance Classroom Mean scores x⎯⎯1x¯1 = 9.0 x⎯⎯2x¯2 = 10.2 Sample std. dev. s1 = 2.1 s2 = 2.4 Number of students n1 = 19 n2 = 19 Assume μ1 is the mean score of distance learning and μ2 is the mean score of classroom learning. The appropriate hypotheses is H0: μ1 – μ2 = 0 vs. H1: μ1 – μ2 ≠ 0 (b) Specify the decision rule. (Round your answers to 3 decimal places. A negative value should be indicated by a minus sign.) Reject the null hypothesis if tcalc < _______. Or tcalc > ______________. (c) Find the test statistic tcalc. (Round your answer to 4 decimal places. A negative value should be indicated by a minus sign.) tcalc ______________The parameters of my population distribution are: µ = 20 and σ = 5. The parameters of my sample are: Mean = 24 and n = 25. Calculate my sample's Z score on the comparison distribution.A population has a mean of µ = 20. A sample is selected from this population and a treatment is administered to each individual in the sample. The scores from this sample are summarized as follows: n = 16 ,X = 28 ,s2 = 64. Do the sample data support the conclusion that the treatment has a significant effect? Test with α = .05.
- The corrosive effects of various soils on coated and uncoated steel pipe was tested by using a dependent sampling plan. The data collected are summarized below, where d is the amount of corrosion on the coated portion subtracted from the amount of corrosion on the uncoated portion. Does this random sample provide sufficient reason to conclude that the coating is beneficial? Use a = 0.01 and assume normality. n- 40, Σd- 207, Σα? = 6199 (a) Find t. (Give your answer correct to two decimal places.) (ii) Find the p-value. (Give your answer correct to four decimal places.) (b) State the appropriate conclusion. O Reject the null hypothesis, there is significant evidence that the coating is beneficial. Reject the null hypothesis, there is not significant evidence that the coating is beneficial. Fail to reject the null hypothesis, there is significant evidence that the coating is beneficial. Fail to reject the null hypothesis, there is not significant evidence that the coating is beneficial.Two samples were drawn independently from two normal populations. Sample 1: 11.6, 11.35, 10.1, 10.85, 10.35, 10.6, and 11.1.Sample 2: 5.85, 8.85, 9.85, 11.85 and 7.85.Test to determine whether the means of the two population differs (use α=0.05).A researcher reports t(26) = 2.71 for a two independent samples t-test. How many participants were in the entire experiment? a. 28 b. 27 c. 30 d. cannot determine with the information provided
- The corrosive effects of various soils on coated and uncoated steel pipe was tested by using a dependent sampling plan. The data collected are summarized below, where d is the amount of corrosion on the coated portion subtracted from the amount of corrosion on the uncoated portion. Does this random sample provide sufficient reason to conclude that the coating is beneficial? Use ? = 0.01 and assume normality. n = 36, Σd = 227, Σd2 = 6244(a) Find t. (Give your answer correct to two decimal places.)(ii) Find the p-value. (Give your answer correct to four decimal places.)(b) State the appropriate conclusion. Reject the null hypothesis, there is significant evidence that the coating is beneficial.Reject the null hypothesis, there is not significant evidence that the coating is beneficial. Fail to reject the null hypothesis, there is significant evidence that the coating is beneficial.Fail to reject the null hypothesis, there is not significant evidence that the coating is beneficial.In a test of H0: p = 0.40 against Ha: p # 0.40, the sample data yield the test statistics z = 1.78. Find the p-value for this test. Round your answer to 4 decimal places.In a test of H0: p = 0.4 against H1: p ≠ 0.4, a sample of size 100 produces Z = 1.28 for the value of the test statistic. Thus the p-value (or observed level of significance) of the test is approximately equal to:
- What is the standardized test statistic t for a sample with n = 12, xbar = 30.2, s = 2.2, and α = 0.01 if H0: µ =29? Round your answer to the nearest thousandth.Two major automobile manufacturers have produced compact cars with engines of the same size. We are interested in determining whether or not there is a significant difference in the mean MPG (miles per gallon) when testing for the fuel efficiency of these two brands of automobiles. A random sample of eight cars from each manufacturer is selected, and eight drivers are selected to drive each automobile for a specified distance. The following data (in miles per gallon) show the results of the test. Assume the population of differences is normally distributed. Driver Manufacturer A Manufacturer B 1 36 30 2 31 31 3 30 28 4 30 27 5 29 27 6 33 30 7 35 25 8 29 31 The test statistic is 2.316. At ? = 0.10, the null hypothesis should be revised .should not be tested. should be rejected. should not be rejected.