In a survey of 1393 people, 936 people said they voted in a recent presidential election. Voting records show th eligible voters actually did vote. Given that 65% of eligible voters actually did vote, (a) find the probability that ar randomly selected voters, at least 936 actually did vote. (b) What do the results from part (a) suggest? (a) P(X≥ 936) = (Round to four decimal places as needed.) (b) What does the result from part (a) suggest? O A. Some people are being less than honest because P(x ≥ 936) is less than 5%.
In a survey of 1393 people, 936 people said they voted in a recent presidential election. Voting records show th eligible voters actually did vote. Given that 65% of eligible voters actually did vote, (a) find the probability that ar randomly selected voters, at least 936 actually did vote. (b) What do the results from part (a) suggest? (a) P(X≥ 936) = (Round to four decimal places as needed.) (b) What does the result from part (a) suggest? O A. Some people are being less than honest because P(x ≥ 936) is less than 5%.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Question
n a survey of 1393 people, 936 people said they voted in a recent presidential election. Voting records show that 65% of eligible voters actually did vote. Given that 65% of eligible voters actually did vote, (a) find the
Expert Solution
Step 1: Determine the given variable
Given:
This is a binomial distribution question with
n = 1393
p = 0.65
q = 1 - p = 0.35
This binomial distribution can be approximated as Normal distribution since
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