In a study to estimate the proportion of residents in a certain city and its suburbs whofavor the construction of a nuclear power plant, it is found that 77 of 125 urban residentsfavor the construction while only 56 of 100 suburban residents are in favor. Is there asignificant difference between the proportions of urban and suburban residents whofavor construction of the nuclear plant? Make use of a P-value.Click here to view page 1 of the standard normal distribution table.Click here to view page 2 of the standard normal distribution table.Let urban residents correspond to population 1, let suburban residents correspond topopulation 2, and let a success be a resident who favors the construction of a nuclearpower plant. Identify the null and alternative hypotheses.A. Ho: P₁ = P2H₁: P₁ P2D. Ho: P₁ #P2H₁: P₁ = P2Find the test statistic....Find the P-value.B. Ho: P₁ = P2H₁: P₁ P2E. Ho: P₁ = P2H₁: P₁ P2.85 (Round to two decimal places as needed.)(Round to three decimal places as needed.)C. Ho: P₁ > P2H₁: P₁ = P2F. Ho: P1P2H₁: P₁ = P2 A marketing expert for a pasta-making company believes that 50% of pasta lovers preferlasagna. If 13 out of 20 pasta lovers choose lasagna over other pastas, what can beconcluded about the expert's claim? Use a 0.01 level of significance.Click here to view the binomial probability sums table for n=17 and n=18.Click here to view the binomial probability sums table for n=19 and n=20.Let a success be a pasta lover that chooses lasagna over other pastas. Identify the nulland alternative hypotheses.O A. Ho: p > 0.5H₁: p = 0.5D. Ho: p<0.5H₁: p=0.5B. Ho: p = 0.5H₁: p0.5E. Ho: p= 0.5H₁: p <0.5C. Ho: p=0.5H₁: p>0.5.18 (Round to three decimal places as needed.)F. Ho: p0.5H₁: p=0.5The test statistic is a binomial variable X with p= .5 and n = 20.(Type integers or decimals. Do not round.)Find the P-value.

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Answered: In a study to estimate the proportion…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Which statement accurately describes the proportions in the tails of a normal distribution? The proportion in the left-hand tail is smaller than the proportion in the right-hand tail. O Proportions in both the left-hand and right-hand tails tend to be relatively large. OProportions in both tails are the same., O Proportions in both tails are negative.
According to a study, the proportion of people who are satisfied with the way things are going in their lives is 0.86. Suppose that a random sample of 100 people is obtained. Complete parts (a) through (e) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). O A. The response is qualitative because the number of people satisfied can be counted. O B. The response is quantitative because the number of people satisfied can be counted. O C. The response is quantitative because the responses can be classified based on the characteristic of being satisfied or not. YD. The response is qualitative because the responses can be classified based on the characteristic of being satisfied or not. (b) Explain why the sample proportion, p, is a random variable. What is the source of the variability? The sample proportion p is a random variable because the value of p represents a random person included in the…
According to a study conducted by an organization, the proportion of Americans who were afraid to fly in 2006 was 0.10. A random sample of 1,100 Americans results in 121 indicating that they are afraid to fly. Explain why this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). O B. This is not necessarily evidence that the proportion of Americans who are afraid to fly has increased above 0.10 because the probability of obtaining a value equal to or more extreme than the sample proportion is which is not unusual. (Round to four decimal places as needed.)
It turns out that 83 of 125 Republicans compared to 56 of 125 Democrats in the Congress are supporting a trillion-dollar rescue package to for the economy. Help analysts understand whether there is a significant difference between the opinions of Republican and Democrat populations against the rescue package (assuming that they can tolerate 5% Type I error). Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. (a) Identify the null and alternative hypotheses (1:Democrats, 2:Republicans). O A. Ho: P1= P2 against H,: p, # p2 O B. Ho: P1 = P2 against H,: P P2 O D. Ho: P1 P2 against H,: P1 = P2 (b) The z value can be computed as (Round to two decimal places including any zeros.) (c) The p-value is the total tail probability corresponding to the calculated test value, which is then compared to a. In a two-tailed test, this is 2P(Z> z) (assuming z> 0) or, in a right-tailed test, this is P(Z>z). The p-value…
Forest rangers believe that 30% of trees in a large national forest have a leaf fungus. A survery team will inspect a sample of 200 trees. a. Show the steps needed to justify and use a normal model to describe the percentage of fungus-infected trees that may appear in this sample. b. What proportion of infected trees in this sample would lead you to believe the true proportion of ifected trees is higher than the rangers believe?
A survey of 2305 adults in a certain large country aged 18 and older conducted by a reputable polling organization found that 411 have donated blood in the past two years. Complete parts (a) through (c) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). A Question Help (a) Obtain a point estimate for the population proportion of adults in the country aged 18 and older who have donated blood in the past two years. p= 0.178 (Round to three decimal places as needed.) (b) Verify that the requirements for constructing a confidence interval about p are satisfied. The sample a simple random sample, the value of is which is 10, and the less than or equal to 5% of the (Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer. 1 part remaining Clear All Check Answer PAES MAY W 4 F12 F11 F9 F10 F8 F7 F6 吕口 F3 F5 F4 F2 & * $ % 7 8. 2 3 4 T Y U E R Q G H iİŞ
According to a survey in a country, 32% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because n <0.05N and np(1 – p)< 10 GB. Approximately normal because n<0.05N and np(1 - p) 2 10 CC. Not normal because ns0.05N and np(1 - p) 2 10 D. Approximately normal because n<0.05N and np(1 - p)< 10 Determine the mean of the sampling distribution of p. (Round to two decimal places as needed.) p Enter your answer in the answer box and then click Check Answer. ? 6. parts remaining Clear All Check Answer
It is claimed that the proportion of adults with at least one chronic disease in a certain country might be more than the reported number, which is only 25%. A random sample of 85 adults are surveyed, of which 28 are found to suffer from at least one chronic disease. Use a 0.01 level of significance to test the above claim. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard nomal distribution table. (a) Identify the null and alternative hypotheses. O A. H,: p= 0.25 against H,: p 0.25 OD. Hp: p>0.25 against H,: p=0.25 O E. H,:p= 0.25 against H,: p 0.25 OF. H:p OC. z (c) The z value for test can be calculated as (Round to two decimal places including any zeros.) (d) Make an appropriate conclusion. O A. Reject the null hypothesis because there is not significant evidence that more than 25% of the adults suffer from at least one chronic disease. O B. Do not reject the null hypothesis because there is not significant evidence that…
Suppose that the diameters of oak trees are normally distributed with a mean of 4.000 feet and a standard deviation of 0.375 feet. What is the probability of sampling a set of 87 oak trees and finding their mean to differ from the population mean by less than 0.1 feet in diameter? Your answer should be from the cumulative normal distribution table.
In a recent study, the distances of certain raptor nests to the nearest marshland were studied. The study found that these distances are normally distributed with mean 4.52 km and standard deviation 0.85 km. Let Y be the distance of a randomly selected nest to the nearest marshland. Complete parts (a) and (b). Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. Determine P(Y > 5). P(Y > 5) = (Round to four decimal places as needed.)
In a recent poll, 45% of survey respondents said that, if they only had one child, they would prefer the child to be a boy. Suppose you conducted a survey of 160 randomly selected students on your campus and find that 79 of them would prefer a boy. Complete parts (a) and (b) below. Click here to view the standard normal distribution table (page 1). LOADING... Click here to view the standard normal distribution table (page 2). LOADING... (a) Use the normal approximation to the binomial to approximate the probability that, in a random sample of 160 students, at least 79 would prefer a boy, assuming the true percentage is 45%. The probability that at least 79 students would prefer a boy is 3636. (Round to four decimal places as needed.)

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