In a study, the mean number of days that 124 adolescents in substance abuse treatment used medical marijuana in the last 5 months was 119.17. Assuming the population standard deviation is 34 days, a 95% confidence interval for the mean number of days, µ, of medical marijuana use in the last 5 months of all adolescents in substance abuse treatment is from 113.19 days to 125.15 days; this interval's margin of error is 5.98 days. Complete parts (a) through (d) below. Olislı k
In a study, the mean number of days that 124 adolescents in substance abuse treatment used medical marijuana in the last 5 months was 119.17. Assuming the population standard deviation is 34 days, a 95% confidence interval for the mean number of days, µ, of medical marijuana use in the last 5 months of all adolescents in substance abuse treatment is from 113.19 days to 125.15 days; this interval's margin of error is 5.98 days. Complete parts (a) through (d) below. Olislı k
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question Help O
In a study, the mean number of days that 124 adolescents in substance abuse treatment used medical marijuana in the last 5 months was 119.17. Assuming the
population standard deviation is 34 days, a 95% confidence interval for the mean number of days, µ, of medical marijuana use in the last 5 months of all adolescents in
substance abuse treatment is from 113.19 days to 125.15 days; this interval's margin of error is 5.98 days. Complete parts (a) through (d) below.
Click here to view page 1 of the table of areas under the standard normal curve.
Click here to view page 2 of the table of areas under the standard normal curve.
The 95% confidence interval is from 103.57 day(s) to 127.51 day(s).
(Round to two decimal places as needed.)
b. Compare the 95% confidence intervals obtained in part (a) and in the original study by drawing a graph. Choose the correct graph below.
O A.
В.
95% Cl for u
95% CI for u
(n = 124)
(n = 124)
95% Cl for u
95% Cl for u
(n = 31)
(n = 31)
108
118
128
104
118
132
OD.
95% CI for u
95% Cl for u
(n = 124)
(n = 124)
95% Cl for u
95% Cl for u
(n = 31)
(n = 31)
100
114
128
112
120
128
c. Compare the margins of error for the two 95% confidence intervals.
The margin of error for the interval obtained in part (a) is
day(s), which is
the margin of error of the interval obtained in the original study.
(Round to two decimal places as needed )"
Transcribed Image Text:8.2.81
Question Help O
In a study, the mean number of days that 124 adolescents in substance abuse treatment used medical marijuana in the last 5 months was 119.17. Assuming the
population standard deviation is 34 days, a 95% confidence interval for the mean number of days, µ, of medical marijuana use in the last 5 months of all adolescents in
substance abuse treatment is from 113.19 days to 125.15 days; this interval's margin of error is 5.98 days. Complete parts (a) through (d) below.
Click here to view page 1 of the table of areas under the standard normal curve.
Click here to view page 2 of the table of areas under the standard normal curve.
The 95% confidence interval is from 103.57 day(s) to 127.51 day(s).
(Round to two decimal places as needed.)
b. Compare the 95% confidence intervals obtained in part (a) and in the original study by drawing a graph. Choose the correct graph below.
O A.
В.
95% Cl for u
95% CI for u
(n = 124)
(n = 124)
95% Cl for u
95% Cl for u
(n = 31)
(n = 31)
108
118
128
104
118
132
OD.
95% CI for u
95% Cl for u
(n = 124)
(n = 124)
95% Cl for u
95% Cl for u
(n = 31)
(n = 31)
100
114
128
112
120
128
c. Compare the margins of error for the two 95% confidence intervals.
The margin of error for the interval obtained in part (a) is
day(s), which is
the margin of error of the interval obtained in the original study.
(Round to two decimal places as needed )
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Question Help
For the provided sample mean, sample size, and population standard deviation, complete parts (a) through (c) below. Assume that x is normally distributed.
x = 38, n = 16, o = 8
%3D
a. Find a 95% confidence interval for the population mean.
The 95% confidence interval is from 34.08 to 41.92.
(Round to two decimal places as needed.)
b. Identify and interpret the margin of error.
The margin of error is 3.92.
(Round to two decimal places as needed.)
Interpret the margin of error. Choose the correct answer below.
O A. We can be 95% confident that any possible value of the variable is within the margin of error of the sample mean, 38.
B. We can be 95% confident that any possible sample mean is within the margin of error of 38.
We can be 95% confident that any possible value of the variable is within the margin of error of the population mean, µ.
D. We can be 95% confident that the population mean, µ, is within the margin of error of the sample mean, 38.
c. Express the endpoints of the confidence interval in terms of the point estimate and the margin of error.
The 95% confidence interval is
(Round to two decimal places as needed.)"
Transcribed Image Text:Y 8.1.15
Question Help
For the provided sample mean, sample size, and population standard deviation, complete parts (a) through (c) below. Assume that x is normally distributed.
x = 38, n = 16, o = 8
%3D
a. Find a 95% confidence interval for the population mean.
The 95% confidence interval is from 34.08 to 41.92.
(Round to two decimal places as needed.)
b. Identify and interpret the margin of error.
The margin of error is 3.92.
(Round to two decimal places as needed.)
Interpret the margin of error. Choose the correct answer below.
O A. We can be 95% confident that any possible value of the variable is within the margin of error of the sample mean, 38.
B. We can be 95% confident that any possible sample mean is within the margin of error of 38.
We can be 95% confident that any possible value of the variable is within the margin of error of the population mean, µ.
D. We can be 95% confident that the population mean, µ, is within the margin of error of the sample mean, 38.
c. Express the endpoints of the confidence interval in terms of the point estimate and the margin of error.
The 95% confidence interval is
(Round to two decimal places as needed.)
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