In a study of 295,245 cell phone users, it was found that 48 developed cancer of the brain or nervous system. Assuming that cell phones have no effect, there is a 0.000224 probability of a persondeveloping cancer of the brain or nervous system. We therefore expect about 67 cases of such cancer in a group of 295,245 people. Estimate the probability of 48 or fewer cases of such cancer in aof 295,245 people. What do these results suggest about media reports that cell phones cause cancer of the brain or nervous system?group(a) P(x <48) =|(Round to four decimal places as needed.)Enter your answer in the answer box and then click Check Answer?partremaininaCheck AnswerClear Alljavascript doExercise(8);Ancwered sbout 6 hours ago5:29 PM^12/3/2019eaO EtType here to search8

The value of probability P (X ≤ 48) is obtained below:From the given information, let the random…

Answered: In a study of 295,245 cell phone users,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to a study on the effects of smoking by pregnant women on rates of asthma in their children, for expectant mothers who smoke 20 cigarettes per day, 22.2% of their children developed asthma by the age of two in the US. A biology professor at a university would like to test if the percentage is different in another country. She randomly selects 319 women who only deliver one child and smoke 20 cigarettes per day during pregnancy in that country and finds that 82 of the children developed asthma by the age of two. In this hypothesis test, Do the hypothesis test. Use a level of significance of a = 0.05; Use the unrounded values in Excel to find the answers for #3 and #4 1. This is an example of 2. Find the standard error. 3. Find the z value. Question 10 V a hypothesis test.
In a study of 354,079 cell phone users, it was found that 139 developed cancer of the brain or nervous system. Assuming that cell phones have no effect, there is a 0.000469 probability of a person developing cancer of the brain or nervous system. We therefore expect about 167 cases of such cancer in a group of 354,079 people. Estimate the probability of 139 or fewer cases of such cancer in a group of 354,079 people. What do these results suggest about media reports that cell phones cause cancer of the brain or nervous system? (a) P(x s139) = | (Round to four decimal places as needed.) %3D
The National Academy of Science reported that 41% of research in mathematics is published by US authors. The mathematics chairperson of a prestigious university wishes to test the claim that this percentage is no longer 41%. He has no indication of whether the percentage has increased or decreased since that time. He surveys a simple random sample of 186 recent articles published by reputable mathematics research journals and finds that 92 of these articles have US authors. Does this evidence support the mathematics chairperson’s claim that the percentage is no longer 41%? Use a 0.05 level of significance. Step 1 of 3: State the null and alternative hypotheses for the test. circle the answer below. H0 p=0.41 ha: p⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯0.41 A.<B.≠C.> Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places Step 3 of 3: Draw a conclusion and interpret the decision. A. We reject the null hypothesis and conclude that there is insufficient evidence at a…
A random sample of n1 = 157 people ages 16 to 19 were taken from the island of Oahu, Hawaii, and 12 were found to be high school dropouts. Another random sample of n2 = 129 people ages 16 to 19 were taken from Sweetwater County, Wyoming, and 6 were found to be high school dropouts. Do these data indicate that the population proportion of high school dropouts on Oahu is different (either way) from that of Sweetwater County? Use a 1% level of significance. (a) What is the level of significance? What is the value of the sample test statistic? (Test the difference p1 − p2. Do not use rounded values. Round your final answer to two decimal places.) (c) Find (or estimate) the P-value. (Round your answer to four decimal places.)
Teenagers who do not sleep well or long enough may have a higher risk of raised blood pressure, which could lead to cardiovascular disease later in life. The odds of raised blood pressure increase 3.5 times for those who have trouble falling asleep at night or who wake up too early and 2.5 times for those with sleeping periods of fewer than 6.5 hours. A health psychologist is interested in studying teenagers who have diastolic blood pressure scores in the top 20%. Diastolic blood pressure scores for teenagers follow a normal distribution with μ = 72 and σ = 10. Use the Distributions tool to help answer the questions that follow. The minimum z-score necessary to be in the top 20% of the diastolic blood pressure distribution is z =0.842 . Use this z-score to determine X, the corresponding diastolic blood pressure score. X = 80.42 This score, X, is the 80th percentile of diastolic blood pressure scores among teenagers. The percentile rank of this score is 80%…
It is believed that 11% of all Americans are left-handed. A college needs to know how many left-handed desks to place in the big lecture halls being constructed on its campus. In a random sample of 210 students from that college, whether or not a student was left-handed was recorded for each student. The college wants to know if the data provide enough evidence to show that students at this college have a different percentage of left-handers than the general American population? State the random variable, population parameter, and hypotheses. State the Type I and Type II errors in the context of this problem.a) The symbol for the random variable involved in this problem is The wording for the random variable in context is as follows: b) The symbol for the parameter involved in this problem is The wording for the parameter in context is as follows: c) Fill in the correct null and alternative hypotheses: H0:H0: HA:HA:…
It is believed that 11% of all Americans are left-handed. A college needs to know how many left-handed desks to place in the big lecture halls being constructed on its campus. In a random sample of 210 students from that college, whether or not a student was left-handed was recorded for each student. The college wants to know if the data provide enough evidence to show that students at this college have a higher percentage of left-handers than the general American population? State the random variable, population parameter, and hypotheses. State the Type I and Type II errors in the context of this problem.
In a study of 349,212 cell phone users, it was found that 26 developed cancer of the brain or nervous system. Assuming that cell phones have no effect, there is a 0.000109 probability of a person developing cancer of the brain or nervous system. We therefore expect about 39 cases of such cancer in a group of 349,212 people. Estimate the probability of 26 or fewer cases of such cancer in a group of 349,212 people. What do these results suggest about media reports that cell phones cause cancer of the brain or nervous system? (a) P(xs 26) = (Round to four decimal places as needed.) (b) What does the result from part (a) suggest about the media reports? O A. The media reports appear to be correct because one would expect that more than 26 cell phone users would develop cancer and the study offers significant evidence to support this. B. The media reports appear to be incorrect because one would expect that more than 39 cell phone users would develop cancer. In fact, the study may offer…
The drug Finasteride is marketed as Propecia to help protect against male pattern baldness, and it also may protect against prostate cancer. A large sampleof healthy men over age 55 were randomly assigned to receive either a daily Finasteride pill or a placebo. The study lasted seven years and the men had annual check-ups and a biopsy at the end of the study. Prostate cancer was found in 804 of 4368 men taking Finasteride and in 1145 of the 4692 men taking a placebo. the 95% confidence interval for the risk difference is (-0.077, -0.043). Compared to this confidence interval, a 98% confidence interval for the risk difference is: a.) wider b.) there is not enough information provided to decide c.) half the width d.) the same width e.) narrower
It is believed that 11% of all Americans are left-handed. A college needs to know how many left-handed desks to place in the big lecture halls being constructed on its campus. In a random sample of 210 students from that college, whether or not a student was left-handed was recorded for each student. The college wants to know if the data provide enough evidence to show that students at this college have a higher percentage of left-handers than the general American population? State the random variable, population parameter, and hypotheses. State the Type I and Type II errors in the context of this problem.
In a study of 235,722 cell phone users, it was found that 109 developed cancer of the brain or nervous system. Assuming that cell phones have no effect, there is a 0.000477 probability of a person developing cancer of the brain or nervous system. We therefore expect about 113 cases of such cancer in a group of 235,722 people. Estimate the probability of 109 or fewer cases of such cancer in a group of 235,722 people. What do these results suggest about media reports that cell phones cause cancer of the brain or nervous system? (a) P(x ≤ 109) = (Round to four decimal places as needed.)
In a study of 213,270 cell phone users, it was found that 77 developed cancer of the brain or nervous system. Assuming that cell phones have no effect, there is a 0.000397 probability of a person developing cancer of the brain or nervous system. We therefore expect about 85 cases of such cancer in a group of 213,270 people. Estimate the probability of 77 or fewer cases of such cancer in a group of 213,270 people. What do these results suggest about media reports that cell phones cause cancer of the brain or nervous system? (a) P(x ≤ 77) = (Round to four decimal places as needed.)

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