Answered: In a single slit Fraunhofer diffraction… | bartleby

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In a single slit Fraunhofer diffraction the intensity distribution is
given by
sin' B
I(0) = I,
1
Where, B =- kd sin 0
2
Derive the condition of constructive and destructive interference.
Also, sketch the intensity distribution graph.

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Two slits are illuminated by a monochromatic plane wave of wavelength k. The slits have a width a=3k, and the distance between them is d=9k. (a) Determine if there are any interference maxima that are missing from the two-slit interference pattern because the minimum of the diffraction occurs in the same direction. Find all angles that lead to such missing orders. (b) Calculate the intensity of the first two-slit constructive interference fringe (|m|=1) relative to I(1), the intensity of the central peak.
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Consider the following. (a) Find the angle (theta) locating the first minimum in the Fraunhofer diffraction pattern of a single slit of width 0.210 mm, using light of wavelength 555 nm.(b) Find the angle locating the second minimum.
There is a circular slit with its radius a = 0.1mm. The distance between the slit plane and detector plane is given by R=1m. Roughly estimate the requirement of the wavelength of incident light for Fraunhofer diffraction with appropriate justification.
In a double-slit experiment, d 21um and the wavelength of the light is A = 431nm. The intensity of light at the center of the central fringe is measured to be 21 kW -. Determine the intensity at a point that is at an angle of 1.4° from m? the center of the central fringe lin HW m?). (Use the ideal double slit intensity formula)