In a single-factor ANOVA test, the test statistic is F* = 4.25. The rejection region is F> 3.06 for the a= 0.05, F > 3.8 for a = 0.025, and F > 4.89 for a = 0.01. For this test, the approximate p-value is%3D%3Dgreater than 0.05O between 0.025 and 0.05O between 0.01 and 0.025O approximately 0.05

Given Fstatistic=4.25 We want to find the approximately p value.

Answered: In a single-factor ANOVA test, the test…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Find the area to the right of the z-score 0.03 under the standard normal curve. z−0.2−0.10.00.10.000.42070.46020.50000.53980.010.41680.45620.50400.54380.020.41290.45220.50800.54780.030.40900.44830.51200.55170.040.40520.44430.51600.55570.050.40130.44040.51990.55960.060.39740.43640.52390.56360.070.39360.43250.52790.56750.080.38970.42860.53190.57140.090.38590.42470.53590.5753 Use the value(s) from the table above. Provide your answer below: FEEDBACK Content attribution- Opens a dialog
Find the z-score such that: (a) The area under the standard normal curve to its left is 0.667 Z = (b) The area under the standard normal curve to its left is 0.9135 Z= (c) The area under the standard normal curve to its right is 0.0881 Z= (d) The area under the standard normal curve to its right is 0.2523 Z=
Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is less than 3.78 and draw a sketch of the region. What is the probabilty?
You are using a z-test to test H0: u=400 vs Ha: u<400 at the a=.05 level. What would the rejection region be for this test?
Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is less than −1.11 and draw a sketch of the region?
Draw the standard normal curve that corresponds to an area between z = 0 and z = 2. Then, use the standard normal table to find the area under the curve between these two z-scores.
Determine the area under the standard normal curve that lies to the right of the z-score 0.28 and to the left of the z-score 0.43. 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -0.2 0.4207 0.4168 0.4129 0.4090 0.4052 0.4013 0.3974 0.3936 0.3897 0.3859 -0.1 0.4602 0.4562 0.4522 0.4483 0.4443 0.4404 0.4364 0.4325 0.4286 0.4247 0.0 0.5000 0.5040 0.5080 0.5120 0.5160 0.5199 0.5239 0.5279 0.5319 0.5359 0.1 0.5398 0.5438 0.5478 0.5517 0.5557 0.5596 0.5636 0.5675 0.5714 0.5753 0.2 0.5793 0.5832 0.5871 0.5910 0.5948 0.5987 0.6026 0.6064 0.6103 0.6141 0.3 0.6179 0.6217 0.6255 0.6293 0.6331 0.6368 0.6406 0.6443 0.6480 0.6517 0.4 0.6554 0.6591 0.6628 0.6664 0.6700 0.6736 0.6772 0.6808 0.6844 0.6879 0.5 0.6915 0.6950 0.6985 0.7019 0.7054 0.7088 0.7123 0.7157 0.7190 0.7224
Find the z-score such that: (a) The area under the standard normal curve to its left is 0.5699z = (b) The area under the standard normal curve to its left is 0.742z = (c) The area under the standard normal curve to its right is 0.1525z = (d) The area under the standard normal curve to its right is 0.3269z =
What is the standard normal distribution for P(- 2.44 < z < - 1.76)?
Find the z-scores for which 28% of the distribution's area lies between −z and z.
Recall that if the sample proportion of defective cartridges is more than 0.02, the entire shipment will be returned to the vendor. We have been asked to determine the probability that a shipment will be returned if the true proportion of defective cartridges in the shipment is 0.06. This means we will find the area in the right tail of the standard normal distribution above the z-score of -2.55. Recall that n = 230, p = 0.02, and p = 0.06. Use the appropriate table in Appendix A or technology to find the probability. (Round your answer to four decimal places.) P(Returned) = P(p > 0.02) = P(z > -2.55) 0.9957 The approximate probability that a shipment will be,returned. if the true proportion of defective cartridges in the shipment is 0.06, rounded to four decimal places, is Enter a number.
Consider a test of Ho : u = 4. In each of the following cases, give the rejection region, assuming that the test statistics follows a standard Normal distribution. (a) H. : u > 4, a = 0.1 (b) H. : u <4, a = 0.01 (c) Ha : 4# 4, a = 0.05

SEE MORE QUESTIONS

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS

In a single-factor ANOVA test, the test statistic is F* = 4.25. The rejection region is F> 3.06 for the a = 0.05, F > 3.8 for a = 0.025, and F > 4.89 for a = 0.01. For this test, the approximate p-value is O greater than 0.05 O between 0.025 and 0.05 O between 0.01 and 0.025 O approximately 0.05