What is the standard normal distribution for P(- 2.44 < z < - 1.76)?
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A: We have to find the probability for a standard normal distribution. P (Z > -1.12).
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A: Using Normal table, P(Z < -1) = 0.1587
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A:
Q: The total area under the standard normal curve to the left of z = - 0.49 or to the right of z = 1.44…
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Given information-
We have given the standard normal distribution.
P (-2.44 < z < -1.76)
We have to find the probability.
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- Which of the following is not a characteristic of the normal distribution? (a) the mean, median and mode are equal (b) the mean is always zero (c) it is a symmetric distribution (d) it is bell-shaped the area under the curve is equal to 1Q4: If z follows a standard normal distribution, then P(z > 1.96) = 0.9750. 1- True 2- FalseAssume that all are standard normal distribution P(-2.11<z<4.00)
- Find the proportion of observations from the standard Normal distribution that are: a) P(Z<-0.12) = b) P(0.41<Z<1.15) = Round to 3 decimal places.Assume Z has a standard normal distribution. Use Appendix Table III to determine the value for z that solves each of the following: (a) P(- z < Z < z) = 0.95. z = 1.96 (Round the answer to 2 decimal places.) (b) P(- z < Z < z) = 0.99. z = 2.576 (Round the answer to 2 decimal places.) (c) P(-z< Z < z) = 0.66. z = i (d) P(- z < Z < z) = 0.9973. z = (Round the answer to 2 decimal places.) (Round the answer to 1 decimal place.)Which of these are characterize/s a normal distribution curve? (Check all that applies.) symmetric asymptotic unimodal total area under it is 1
- Use the Central Limit Theorem to find the probability of the indicated event, assuming that the distribution of the population data is unknown. The amount of time students spend checking their phones during a lecture period has a mean of 9 minutes and standard deviation of 2 minutes. What is the probability that a sample of 30 students will spend an average of at most 9.7 minutes checking their phones during a lecture period? Standard Normal Distribution Table P( X̄ < 9.7)=__The average number of miles (in thousands) that a car's tire will function before needing replacement is 68 and the standard deviation is 12. Suppose that 15 randomly selected tires are tested. Round all answers to 4 decimal places where possible and assume a normal distribution. What is the distribution of X? X ~ N(___,___) What is the distribution of ¯x? x¯ ~ N(___,____) If a randomly selected individual tire is tested, find the probability that the number of miles (in thousands) before it will need replacement is between 65 and 66.8. ______ For the 15 tires tested, find the probability that the average miles (in thousands) before need of replacement is between 65 and 66.8. _______ For part d), is the assumption that the distribution is normal necessary? __Yes ___ NoThe shaded region under a Normal distribution with mean 0 and standard deviation 1 (Standard Normal distribution) is shown. Which of the following is the best choice that corresponds to the shaded region? Select one. mean Probability of z <+1.5 Probability of z-1.5 Probability of ze 1.5 Probability of z +1.5