In a sand cone density test, the volume of the ottawa sand released in the field was 0.17 cubic ft, and the volume of the cone was 0.09 cubmic ft, and the weight of the dirt collected from the field pit was 8.2 lbs, the soil wet density is: None of the answers 48.2 pcf 117.4 pcf 102.5 pcf
The following formula must be used to determine the soil's moist density:
Wet Density (pcf) = Weight of soil collected / Volume of sand cone
We must first determine the size of the hole from which the soil was taken. To calculate this, divide the weight of the sand used by the bulk density of the sand, which is often supplied by the manufacturer. Assuming the Ottawa sand has a bulk density of 100 lb/ft3:
Sand volume is determined by its weight and bulk density.
Sand used: 0.09 cubic feet
Next, we can get the volume of the hole using the volume of the cone (0.09 ft3) and the volume of the expelled sand (0.17 ft3):
The volume of hole = Sand discharged volume - Cone volume
Hole volume equals 0.17 ft3 minus 0.09 ft3.
The volume of hole: 0.08 cubic feet
We can now determine the wet density:
Weight of soil taken divided by hole volume equals wet density.
Wet Density: 8.2 pounds per cubic foot
Density of Water = 102.5 PCF
As a result, the soil has a wet density of 102.5 pcf. The correct response is thus "102.5 pcf."
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