In a rotational equilibrium experiment, a group takes a one-meter ruler with a uniformly distributed mass of 250 grams. A thread will be tied to the ruler 15 cm to the left of the center of mass, swinging the ruler. Then the group places a mass m1 = 170 gr at the 20 cm position on the ruler. Then they place a mass m2 = 155 gr in the 40 cm position. A mass m3 is placed at the 15 cm position on the ruler. Determine: a) The lever arm for mass m1, m2 and m3. b) The lever arm of the ruler. c) The value of the mass m3 that balances the system.

icon
Related questions
Question

In a rotational equilibrium experiment, a group takes a one-meter ruler with a uniformly distributed mass of 250 grams. A thread will be tied to the ruler 15 cm to the left of the center of mass, swinging the ruler. Then the group places a mass m1 = 170 gr at the 20 cm position on the ruler. Then they place a mass m2 = 155 gr in the 40 cm position. A mass m3 is placed at the 15 cm position on the ruler. Determine:

a) The lever arm for mass m1, m2 and m3.

b) The lever arm of the ruler.

c) The value of the mass m3 that balances the system.

Expert Solution
steps

Step by step

Solved in 3 steps with 1 images

Blurred answer
Similar questions