In a reaction, gaseous reactants form a liquid product. The heat absorbed by the surroundings is 4.7 MJ, and the work done on the system is 19.3 kcal. Calculate AE (in kJ). Be sure to include the correct sign (+/-). Enter to 0 decimal places.
In a reaction, gaseous reactants form a liquid product. The heat absorbed by the surroundings is 4.7 MJ, and the work done on the system is 19.3 kcal. Calculate AE (in kJ). Be sure to include the correct sign (+/-). Enter to 0 decimal places.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![In a reaction, gaseous reactants form a liquid product. The heat absorbed by the surroundings is 4.7
MJ, and the work done on the system is 19.3 kcal. Calculate AE (in kJ). Be sure to include the
correct sign (+/-). Enter to 0 decimal places.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbce55b4b-5725-49f6-aef8-70bc533ee1b1%2F2ec47157-b670-4cfe-b9d2-918e4165aaef%2Fs28iks_processed.jpeg&w=3840&q=75)
Transcribed Image Text:In a reaction, gaseous reactants form a liquid product. The heat absorbed by the surroundings is 4.7
MJ, and the work done on the system is 19.3 kcal. Calculate AE (in kJ). Be sure to include the
correct sign (+/-). Enter to 0 decimal places.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1) Given Data
Given 1)heat absorbed by surrounding is 4.7 MJ
2)work done on the system is 19.3 kcal Here,
Heat absorbed by surrounding
Means
Heat released by system
And heat released by system = -ve
And work done on system = +ve
So,
heat absorbed by system = Q = - 4.7 MJ
work done on the system = W = + 19.3 kcal
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