In a reaction, 80.0 mL of 0.160 M HPro was reacted with 20.0 mL of 0.140 M NaOH. (Na* is a spectator ion and has been omitted.) HPro (ag) + OH- (ag) → H2O () + Pro- (ag) 6) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end of this "big change" reaction. (The LR concentration will be zero.) 7) Using your values of HPrO and NaPro in the answer to the previous problem, plug into the K, equation to solve for the value of [H*]. 8) Calculate the pH of this final solution.
In a reaction, 80.0 mL of 0.160 M HPro was reacted with 20.0 mL of 0.140 M NaOH. (Na* is a spectator ion and has been omitted.) HPro (ag) + OH- (ag) → H2O () + Pro- (ag) 6) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end of this "big change" reaction. (The LR concentration will be zero.) 7) Using your values of HPrO and NaPro in the answer to the previous problem, plug into the K, equation to solve for the value of [H*]. 8) Calculate the pH of this final solution.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Answer all questions 6-12 showing complete work.
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![In a reaction, 80.0 mL of 0.160 M HPro was reacted with 20.0 mL of 0.140 M NAOH. (Na* is a
spectator ion and has been omitted.)
HPro (aq) + OH- (ag) → H20 () + Pro- (ag)
6) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end
of this "big change" reaction. (The LR concentration will be zero.)
7) Using your values of HPTO and NaPro in the answer to the previous problem, plug into the K,
equation to solve for the value of [H*].
8) Calculate the pH of this final solution.
9) Write the dissociation reaction for the weak base LiPro (Pro) in water.
10) Write the mass action expression for this equation, which is equal to Ko.
11) Since Kw = Ka x Ko, solve for the mathematical value of Kp.
12) Calculate the following values for a 0.138 M Ca(Pro)2 solution:
(a) the [OH] in a 0.138 M Ca(Pro)2 solution. (Use an “ICE" table)
(b) the pH of a 0.138 M Ca(Pro)2 solution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd9f79989-d9c4-46f2-a3af-be71864f1886%2F1dc8e7a8-e811-497b-af64-e70ab24feb3f%2Fko8501_processed.png&w=3840&q=75)
Transcribed Image Text:In a reaction, 80.0 mL of 0.160 M HPro was reacted with 20.0 mL of 0.140 M NAOH. (Na* is a
spectator ion and has been omitted.)
HPro (aq) + OH- (ag) → H20 () + Pro- (ag)
6) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end
of this "big change" reaction. (The LR concentration will be zero.)
7) Using your values of HPTO and NaPro in the answer to the previous problem, plug into the K,
equation to solve for the value of [H*].
8) Calculate the pH of this final solution.
9) Write the dissociation reaction for the weak base LiPro (Pro) in water.
10) Write the mass action expression for this equation, which is equal to Ko.
11) Since Kw = Ka x Ko, solve for the mathematical value of Kp.
12) Calculate the following values for a 0.138 M Ca(Pro)2 solution:
(a) the [OH] in a 0.138 M Ca(Pro)2 solution. (Use an “ICE" table)
(b) the pH of a 0.138 M Ca(Pro)2 solution.
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