possibleIn a random sample of twelve people, the mean driving distance to work was 18.9 miles andthe standard deviation was 6.3 miles. Assume the population is normally distributed and usethe t-distribution to find the margin of error and construct a 95% confidence interval for thepopulation mean u. Interpret the results.Identify the margin of error.(Round to one decimal place as needed.)Construct a 95% confidence interval for the population mean.(Round to one decimal place as needed.)Interpret the results. Select the correct choice below and fill in the answer box to completeyour choice.(Type an integer or a decimal. Do not round.)O A. It can be said that % of the population has a driving distance to work (in miles)that is hetween the interval's endpointsli

given data sample size (n) = 12sample mean ( x¯ ) = 18.9sample standard deviatio (s) = 6.395% ci for…

Answered: In a random sample of twelve people,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 48 business days, the mean closing price of a certain stock was $118.91. Assume the population standard deviation is $10.35. The 90% confidence interval is ( (Round to two decimal places as needed.) The 95% confidence interval is (Round to two decimal places as needed.) Which interval is wider? Choose the correct answer below. O The 90% confidence interval O The 95% confidence interval Interpret the results. OA. You can be 90% confident that the population mean price of the stock is outside the bounds of the 90% confidence interval, and 95% confident for the 95% interval. OB. You can be certain that the population mean price of the stock is either between the lower bounds of the 90% and 95% confidence intervals or the upper…
Construct a confidence interval for the mean of the paired differences for the two populations with the following information. Round the endpoints of the interval to three decimal places, if necessary. n=37n=37, d¯=2.191d¯=2.191, α=0.1α=0.1, sd=0.411sd=0.411
Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ.Assume that the population has a normal distribution. Thirty randomly selected students took the calculus final. If the sample mean was 75 and the standard deviation was 13.21 construct a 99% confidence interval for the mean score of all students. Round to two decimal places.
Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution. Thirty randomly selected students took the calculus final. If the sample mean was 76 and the standard deviation was 7.7, construct a 99% confidence interval for the mean score of all students.
A random sample of 82 women showed that the mean number of children reported was 1.87 with a standard deviation of 1.7 . (Interestingly, a sample of 82 men showed a mean of 1.3 children.) Complete parts (a) through (c) below. LOADING... Click the icon to view the t-table. Question content area bottom Part 1 a. Find a 95% confidence interval for the population mean number of children for women. Because the sample size is so large, you can use 1.96 for the critical value of t (which is the same as the critical value of z) if you do the calculations manually. Choose the correct answer below and, if necessary, fill in the answer boxes to complete your choice. (Type integers or decimals rounded to the nearest hundredth as needed. Use ascending order.)
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 32 months from January 2006 through December 2020, the mean number of tornadoes per month in the United States was about 96. Assume the population standard deviation is 116. The 90% confidence interval is (,). (Round to two decimal places as needed.)
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals.From a random sample of 66 dates, the mean record high daily temperature in a certain city has a mean of 85.22 F. Assume the population standard deviation is 15.45 F.
In a random sample of ten people, the mean driving distance to work was 25.5 miles and the standard deviation was 7.3 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 90% confidence interval for the population mean μ. Interpret the results. Identify the margin of error. (Round to one decimal place as needed.) Construct a 90% confidence interval for the population mean. (...) (Round to one decimal place as needed.) Interpret the results. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) OA. % of all random samples of ten people from the population will have a mean driving distance to work (in miles) that is between the interval's endpoints. OB. It can be said that % of the population has a driving distance to work (in miles) that is between the interval's endpoints. OC. With % confidence, it can be said that most driving distances to…
Use the information provided to find the minimum sample size required to estimate an unknown parameter Mean(u). How many students should be randomly selected to estimate the average weekly earnings of students at a university? We want 80% confidence that the sample mean is within $ 3 of the population mean and the population standard deviation is known to be $ 57. Select one: a. 978 b. 362 c. 1388 d. 594 e. 2397

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