In a random sample of males, it was found that 22 write with their left hands and 218 do not. In a random sample of females, itwas found that 64 write with their left hands and 445 do not. Use a 0.01 significance level to test the claim that the rate ofleft-handedness among males is less than that among females. Complete parts (a) through (c) below.a. Identify the test statistic.(Round to two decimal places as needed.)Identify the P-value.P-value =(Round to three decimal places as needed.)What is the conclusion based on the hypothesis test?V the significance level of a = 0.01, sothe null hypothesis. Thereevidence to support the claim that the rate of left-handedness among males is less than that among females.The P-value isb. Test the claim by constructing an appropriate confidence interval.The 98% confidence interval is< (P1 - P2)

Givennumber of males who write with left hand = 22number of males who write with right hand =…

Answered: In a random sample of males, it was…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The Bureau of Labor Statistics reports that the official unemployment rate for Black people was 10.4% and 4.7% for White people in February 2015. Select all correct answers for this question. O The samples of white and black people are independent. The explanatory variable is the unemployment rate. The response variable is the unemployment rate. The response variable is race.
The mean number of sick days an employee takes per year is believed to be about 10. Members of a personnel department do not believe this figure. They randomly survey 8 employees. The number of sick days they took for the past year are as follows: 10; 5; 13; 3; 11; 8; 6; 9. Let X = the number of sick days they took for the past year. Should the personnel team believe that the mean number is about 10? Conduct a hypothesis test at the 5% level.Note: If you are using a Student's t-distribution for the problem, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) What is the test statistic? (If using the z distribution round your answers to two decimal places, and if using the t distribution round your answers to three decimal places.) t = Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence…
According to a Yankelovich poll, women spend an average of 19.1 hours shopping during the month of December, compared to 12.7 hours for men. as in the table below contains the survey data underlying these results, use the 0.01 level in examining whether the sample mean for women is significantly higher than that for men. find the p-value for the test. women men 13,9 11,9 27,6 15,9 11,6 17,9 21,0 12,6 20,9 12,1 20,3 10,5 9,7 11,9 15,6 16,5 22,5 11,2 26,4 5,3 17,0 14,4 23,2 16,3 13,1 10,8 22,1 10,5 21,6
A study of seat belt yielded the randomly selected sample data summarized in the accompanying table. Use a 0.05 significance level to test the claim that the amount of smoking is independent of seat belt use. A plausible theory is that people who smoke dy are less concerned about their health and safety and are therefore less inclined to wear seat belts. Is this theory supported by the sample data? 5 sic Click the icon to view the data table. use. ..... Hа: Heavy Determine the test More info izlet. y of X-(Round to claim Number of Cigarettes Smoked per Day 15-34 Determine the P-v 1-14 35 and over le wh Wear Seat Belts 190 13 36 10 P-Value = (Rou Don't Wear Seat Belts 152 13 45 ww.nur y is that people ry supported by Use a 0.05 signific who smoke are les the sample data? nour seat Done theory is not zed in t Print O A. There is nd supported S Top eat belt. The O B. There is no theory is supportou Dy ao vampIG Gutu. O C. There is sufficient evidence to reject the claim that heavy smokers…
Is the proportion of wildfires caused by humans in the south different from the proportion of wildfires caused by humans in the west? 350 of the 519 randomly selected wildfires looked at in the south were caused by humans while 383 of the 500 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a = 0.01 level of significance? Rectangular Snip a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: Select an answer | (please enter a decimal) Select an answer v Select an answer H1: Select an answer v Select an answer vSelect an answer v (Please enter a decimal) c. The test statistic ? v = (please show your answer to 3 decimal places.)
ANSWER LETTER D,E,F only
light examined data on employment and answered questions regarding why workers separate from their employes. According to the article, the standard deviation of the length of time that women with one job are employed during the first 8 years of their career is 92 weeks. Length of time employed during the first 8 years of career is a left skewed variable. For that variable, do the following tasks. A. determine the sampling distribution of the sample mean for simple random samples of 50 women with one job. Explain your reasoning B. Obtain the probability that the sampling error made in estimating the mean length of time employed by all women with one job by that of a random sample of 50 such women will be at most 20 weeks
A researcher was interested in comparing the amount of time spent watching television by women and by men. Independent random samples of 14 women and 17 men were selected, and each person was asked how many hours he or she spent watching television during the previous week. The summary statistics are as follows. Sample size Mean Standard Deviation Women 14 15.2 3.0 Men 17 11.8 2.5 Is there reason to believe that the average time women spend watching TV is different from the average time men spend watching TV? Test at the 1% level of significance. (Use "NO" for the pooled question) The p-value of the test is
Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 47 of the 52 subjects treated with echinacea developed rhinovirus infections. In a placebo group,92 of the 109 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. A. Identify the test statistic. z equals (Round to two decimal places as needed.) B. Identify the P-value. P-value equals (Round to three decimal places as needed.) C. Test the claim by constructing an appropriate confidence interval. The 99% confidence interval is less than left parenthesis p 1 minus p 2 right parenthesisless than. (Round to three decimal places as needed.)
Several studies showed that after eating a low-fat cereal for two meals a day, subjects had lost some weight.A cereal companyfinanced this research. Identify what is wrong. Choose the correct answer below. A. Since the research is composed of voluntary response samples, there may be key data points missing. B. The data used in the studies is not reliable because it was not measured by the administrator. C. It is questionable that the sponsor is a cereal company because this sponsor can be greatly affected by the conclusion. D. It is not possible to take accurate measurements.
A Pew Research Center survey asked respondents if they would rather live in a place with a slower pace of life or a place with a faster pace of life. The survey also asked the respondent's gender. Consider the following sample data. Do not round your intermediate calculations. Gender Preferred Pace of Life Male Female Slower 229 221 No Preference 18 26 Faster 93 43 a. Is the preferred pace of life independent of gender? Using a .05 level of significance, what is the p-value? Compute the value of the x test statistic (to 3 decimals). Use Table 3 of Appendix B to find the p-value. The p-value is - Select your answer - What is your conclusion? - Select your answer - v that the preferred pace of life is not independent of gender. b. What are the percentage responses for each gender (to 1 decimal)?
Question 2 > The average number of cavities that thirty-year-old Americans have had in their lifetimes is 7. Do twenty- year-olds have a different number of cavities? The data show the results of a survey of 14 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 7, 8, 7, 7, 9, 7, 10, 9, 8, 10, 6, 9, 6, 8 What can be concluded at the a = 0.05 level of significance? %3D a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: |? Select an answer H1: Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that . The data suggest the populaton mean is significantly different from 7 at a = 0.05, so there is sufficient evidence to conclude that the…

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