In a random sample of 254 moviegoers, it was found that 117 of them regularly buy popcorn. Use a 0.14 significance level to test the claim that the percentage of moviegoers who regularly buy popcorn is equal to 50%. a.) State the null and alternative hypothesis using correct symbolic form. Ho: H: b.) What is the positive critical value? (round to two decimal places) Z =
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- A store owner wanted to determine if more than 5% of customers made a purchase after he sent out a text. He sent out 300 texts to 300 randomly selected customers. Out of those 300, 17 made purchases. Is this evidence that if he sent out texts to all of his customers more than 5% would make purchases? What is the appropriate null and alternative hypothesis? Ho: p= 0.05 Ha: p> 0.05 O Ho: phat = 0.05 Ha: phat > 0.05 O Ho: p= 0.056 Ha: p > 0.056 O Ho: mu = 0.05 Hla: mu > 0.05I need the p value Thankyou so muchA researcher is interested in assessing if there are differences in the average number of monthly religious event attendances across religious affiliations. Religious event attendance is measured as an interval-ratio variable: it is the number of events that each survey respondent reported attending in the previous month. Religious affiliation is measured as a nominal variable with the following categories: Protestant, Catholic, Jewish, Muslim, Hindu, Buddhist, other, and not religious. Which of the following hypothesis tests would be appropriate, given the types of variables presented? O Chi-square test O Two-sample difference-of-proportions z-test O ANOVA O One-sample difference-of-proportions z-test
- Men Women H2 A study was done on body temperatures of men and women. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. 11 97.67°F 0.91°F 59 97.35°F 0.73°F a. Use a 0.05 significance level to test the claim that men have a higher mean body temperature than women. What are the null and alternative hypotheses? OB. Ho H =H2 O A. Ho 4, 2H2 H: 1Many Americans believe that women talk more than men. A 1998 study tested this theory by evaluating the number of words spoken daily by men and women. The researcher of the study conducted a two-sample ?t‑test set at a signficance level of α=0.05. The null and alternative hypotheses, ?0 and ?1, are ?0:?M≥?W ?1:?M<?W where ?M represents the mean number of words spoken per day by men, and ?W represents the mean number of words spoken per day by women. The researcher randomly selected 20 men and 27 women and tracked the number of words spoken per day by each individual over a period of time. The sample results are summarized in the table. Population Samplesize Sample mean(words) Sample standarddeviation (words) Men ?M=20 x¯M=12867 ?M=8343 Women ?W= 27 x¯W=16496 ?W=7914 The population variances are unknown and assumed to be unequal. The Welch–Satterthwaite approximation of the degrees of freedom for this test is 39.8360. Assume the conditions for a two‑sample ?t‑test are…A simple random sample of size n= 16 is drawn from a population that is normally distributed. The sample mean is found to be x= 21.2 and the sample standard deviation is found to be s= 6.5. Determine if the population mean is different from 26 at the a= 0.05 level of significance. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). Click here to view the table of criticaltevalmes (a) Determine the null and alternative hypotheses. Ho H,: (Type integers or decimals. Do not round.) (b) Identify the test statistic. (Round to two decimal places as needed.) Approximate the P-value. The P-value is in the range (c) State the conclusion for the test.Test the claim that the proportion of men who own cats is significantly different than 50% at the 0.02 significance level.a.) The null and alternative hypothesis would be: b.) The test is: right-tailed left-tailed two-tailed Based on a sample of 60 men, 59% owned cats c.) The sample proportion ˆp=d.) The test statistic is: (to 2 decimals)e.) At α=α=0.02, the critical value is:± (to 2 decimals)f.) Based on this we: Reject the null hypothesis Fail to reject the null hypothesisThe following data represent a sample of people's smoking habits and their usage of seat belts while in a car. A researcher wants to determine whether smoking habits and seat belt usage are related. Test the researcher's claim at the a = 0.05 level of significance. No Seat Belt Seat Belt Smoke 67 448 Do not Smoke 327 2,187 *Source: Harris Poll a. Determine the null and alternative hypotheses. O Ho: Smoking habits and seat belt usage have the same distribution. Ha: Smoking habits and seat belt usage follow a different distribution. O Ho: Smoking habits and seat belt usage are independent. Ha: Smoking habits and seat belt usage are dependent. b. Determine the test Statistic. Round to two decimal places. c. Determine the p-value. Round to four decimal places. p-value = d. Make a decision. Reject the null hypothesis. O Fail to reject the null hypothesis. e. Make a conclusion. O There is not sufficient evidence to support the claim that smoking habits and seat belt usage are related. O…The data in the accompanying table give the weights (in g) of randomly selected quarters that were minted after 1964. The quarters are supposed to have a median weight of 5.670 g. Use the sign test and a 0.01 significance level to test the claim that the median is equal to 5.670 g. Do quarters appear to be minted according to specifications? Click the icon to view the data. What are the null and alternative hypotheses? O A. Ho: Median weight = 5.670 g H₁: Median weight 5.670 g More Info OB. Ho: Median weight ≤ 5.670 g H₁: Median weight = 5.670 g O D. Ho: Median weight = 5.670 g H₁: Median weight # 5.670 g 0 Post-1964 Quarters 5.5863 5.5764 5.6582 5.5649 5.5844 5.7402 5.7367 5.6057 5.5995 5.6165 5.6448 5.5974 5.6609 5.6363 5.6352 5.5986 5.5797 5.5501 5.6238 5.6462 5.6423 5.7021 5.5481 5.7078 5.6055 5.5324 5.7417 5.6776 5.5924 5.5691 5.5666 5.7287 5.6312 5.6017 5.6626 5.6436 5.6634 5.6132 5.5441 5.6363 -A group of students estimated the length of one minute without reference to a watch or clock, and the times (seconds) are listed below. Use a 0.01 significance level to test the claim that these times are from a population with a mean equal to 60 seconds. Does it appear that students are reasonably good at estimating one minute? 78 92 51 72 52 36 66 70 72 56 70 79 104 95 77 O A. Ho: H= 60 seconds O B. Ho: u= 60 seconds H1: µ> 60 seconds H1: µ< 60 seconds O C. Ho: H+ 60 seconds O D. Ho: µ = 60 seconds H1: µ= 60 seconds H1: µ+60 seconds Determine the test statistic (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. V Họ. There is evidence to conclude that the original claim that the mean of the population of estimates is 60 seconds correct. It that, as a group, the students are reasonably good at estimating one minute. does not appear Click to select your answer(s).…Westjet claims that it's avearage time to fly to Toronto from Thunder Bay is 121 minutes. A random sample of 29 flights from Thunder Bay to Toronto were observed and yeilded a mean of 140 minutes. Assuming that o = 3.1 do we have enough evidence to show that the mean flight is more than 121 minutes? Use a = 0.1 and use our tables. Select the correct null and alternative hypotheses: OA. Ho: X= 140,HA: X 121 OF. Ho X = 140,H₁ : X > 140 OG. None of the above Select the type of distribution to be used in this question: OA. Z-distribution B. t-distribution OC. Chi-Square distribution OD. None of the above The rejection region for this test is: OA. (-∞, -1.28) OB. (1.96,∞) OC. (1.645, ∞) OD. (1.28, ∞) OE. (-∞, -1.96) OF. (-∞, -1.645) OG. (-∞, -1.96) U (1.96,∞) OH. (-∞, -1.28) U (1.28,00) OI. (-∞, -1.645) U (1.645, ∞) OJ. None of the above Test statistic = The conclusion for this test is: OA. Fail to Reject Ho OB. Reject Ho OC. Fail to Reject HA OD. Reject HA OE. None of the aboveIn one study of smokers who tried to quit smoking with nicotine path therapy,38 were smoking one year after the treatment, and 32 were not smoking one year after the treatment. Use a 0.10 significance level to test the claim that among smokers who try to quit with nicotine patch therapy, the majority are smoking a year after the treatment. d. Calculate the test statistic z. Which of these options is closest to z? A. negative 2.02 B. 0.72 C. negative 0.25 D. 2.59 e. Calculate the P-value. Which of these options is closest to the P-value? A. 0.2358 B. 0.2164 C. 0.3359 D. 0.2271 f. State the technical conclusion A. Reject Upper H 0 B. Do not reject Upper H 0 g. State the final conclusion A. There is sufficient evidence to warrant rejection of the claim. B. There is not sufficient evidence to warrant rejection of the claim.…SEE MORE QUESTIONS