In a quasi-static process A - B in which no heat is exchanged with the environment, the pressure P of a certain amount of gas is related to the volume by P = aV-5/3 where a is a constant. Find the quasi-static work done and the net heat absorbed by this system in each of the three processes that take the system from state A to state B. 1. The system is expanding from its initial to its final volume, heat being added to maintain a constant pressure (A B'). The volume is then kept constant and heat is extracted to reduce the pressure to its final value of 10 Pa, (B' B): 2. The volume is increased and heat is supplied to cause the pressure to decrease linearly with volume. 3. The 2 steps in process (1) are performed in reverse order (A A' B).

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In a quasi-static process A B in which no heat is exchanged with the environment,
the pressure P of a certain amount of gas is related to the volume by P = aV-5/3 where a
is a constant.
Find the quasi-static work done and the net heat absorbed by this system in each of the
three processes that take the system from state A to state B.
1. The system is expanding from its initial to its final volume, heat being added to
maintain a constant pressure (A B'). The volume is then kept constant and heat is
extracted to reduce the pressure to its final value of 105 Pa, (B' → B):
2. The volume is increased and heat is supplied to cause the pressure to decrease linearly
with volume.
3. The 2 steps in process (1) are performed in reverse order (A A' → B).
P(105 Pa)
A
B'
32
P ='aV-5/
1
A'
В
1
8
V (liters)
Transcribed Image Text:In a quasi-static process A B in which no heat is exchanged with the environment, the pressure P of a certain amount of gas is related to the volume by P = aV-5/3 where a is a constant. Find the quasi-static work done and the net heat absorbed by this system in each of the three processes that take the system from state A to state B. 1. The system is expanding from its initial to its final volume, heat being added to maintain a constant pressure (A B'). The volume is then kept constant and heat is extracted to reduce the pressure to its final value of 105 Pa, (B' → B): 2. The volume is increased and heat is supplied to cause the pressure to decrease linearly with volume. 3. The 2 steps in process (1) are performed in reverse order (A A' → B). P(105 Pa) A B' 32 P ='aV-5/ 1 A' В 1 8 V (liters)
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