In a public health study, a histogram was plotted showing the number ofcigarettes smoked per day by each subject, as shown below. The numbers ontop of each bar represent its heights. You may assume that the values arespread uniformly across each interval. What is the third quartile (or the 75percentile) of the values?(3.5)(1.5)( 1.5)(0.5)10204080Number of cigarettesbetween 12 and 13 cigarettes20 cigarettesO between 36 and 37 cigarettes60 cigarettesbetween 22 and 23 cigarettes4.3.% per cigarette

Histogram is a graphical representation of the continuous data.

Answered: In a public health study, a histogram…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are given the following set of data. Its mean is 327. 255, 295, 345, 365, 375 If 25 is subtracted from each value, what will be the new mean? A. 270 O B. 327 OC. 315 O D. 302
Which of the following percentiles represents the median of a data set? Select one: a. 100th b. 25th c. 50th d. 75th
Which of these statistics BEST describes the relationship in this scatterplot? Group of answer choices r = –.45 r = .50 r = –1.00 r = .10
A veterinarian recorded how many kittens were born in each litter. This data is summarized in the histogram below. (Note: The last class actually represents "7 or more kittens," not just 7 kittens.) QUESTIONL: What is the frequency of the litter having at most 2 kittens? (PHOTO ATTACHED)
Find the median and lower quartile of the number of wins of the Mariners for 6 years. Years and wins below: 2010/2011/2012/2013/2014/2015 71 61 72 86 89 95 A) Find the median. Show work. B) Find the lower quartile. Show work.
Find the 5 number summary for the data shown 13 24 27 28 38 45 46 48 52 78 84 90 5 number summary: Use the Locator/Percentile method described in your book, not your calculator. Add Work Check Answer
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Nicole has a popular blog about cooking and nutrition and regularly posts articles and videos. She has collected data about the length of time that viewers spent watching two of her recent videos. For each video, she recorded the amount of time (in minutes) that each of 102 viewers spent watching it. The histograms below show the distributions of the two data sets. Each histogram shows time (in minutes) on the horizontal axis and the number of viewers on the vertical axis. The means and standard deviations for the data sets are also given. Video 1 Video 2 25- 25- 20- 20- 15- 15- 10- 10- 5- 5- 0- 19.5 24.5 29.5 34.5 39.5 44.5 49.5 54.5 59.5 64.5 69.5 19.5 24.5 29.5 34.5 39.5 44.5 49.5 54.5 59.5 64.5 69.5 Video 1 mean: 52.05 minutes Video 2 mean: 44.25 minutes Video 1 standard deviation: 12.54 minutes Video 2 standard deviation: 8.16 minutes Nicole wants to use the Empirical Rule to make some approximations about both data sets. Unfortunately, it is appropriate to use the Empirical Rule…
Find the 5 number summary for the data shown 17 21 29 30 36 42 56 60 88 91 94 97 5 number summary:Use the Locator/Percentile method described in your book, not your calculator.
A study was conducted to examine the impact of speaking in public on college students. A class of 15 statistics students participated in the study. At the beginning of a lecture the students recorded their systolic blood pressure. During the lecture the instructor called on each student to stand and answer questions about topics in the lecture. After speaking the students once again recorded their blood pressure. The resulting values are given below along with summary statistics. before 100 123 128 125 136 108 130 113 105 136 146 138 108 149 132 after 141 142 146 136 144 111 132 114 103 133 140 130 100 133 113 difference -41 -19 -18 -11 -8 -3 -2 -1 2 3 6 8 8 16 19 before after difference mean 125.1 127.9 -2.733 st dev 15.26 15.45 15.23 Does this information indicate that blood pressure increased because of speaking? Conduct an appropriate hypothesis test and show appropriate steps. Let μ1 mean systolic blood pressure before speaking in public, and μ2 mean…

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