A poll was conducted on a representative sample of 600 adults living in the United States in order to investigate the decline in cable and satellite TV subscriptions. For this sample, 150 adults revealed that they are "cord cutters," (that is, they canceled their cable/satellite TV service and now only use a video streaming service). You want to estimate p, the true proportion of all US adults who are "cord cutters." Complete parts a through e. Question content area bottom Part 1 a. Find p, the point estimate of p. 0.250.25 (Round to three decimal places as needed.) Part 2 b. Describe the sampling distribution of p. Select the correct choice below and fill in the answer box(es) within your choice. A. Approximately exponential with mean enter your response here and standard deviation enter your response here B. Approximately normal for large samples with mean 0.250.25 and standard deviation 0.01770.0177 (Round to four decimal places as needed.) Your answer is correct. C. Approximately a t-distribution with mean enter your response here, standard deviation enter your response here, and enter your response here degrees of freedom (Type integers or decimals rounded to four decimal places as needed.) D. Approximately Poisson with λ=enter your response here (Round to four decimal places as needed.) E. Approximately uniform with mean enter your response here and standard deviation enter your response here (Round to four decimal places as needed.) Part 3 c. Find a 95% confidence interval for p. 0.2150.215,0.2850.285 (Round to three decimal places as needed.) Part 4 d. Give a practical interpretation of the confidence interval from part c. (Type integers or decimals rounded to three decimal places as needed. Use ascending order.) A. The probability that the true proportion of all US adults who are "cord cutters" is enter your response here lies between enter your response here and enter your response here. B. We can be 9595% confident that the true proportion of all US adults who are "cord cutters" lies between 0.2150.215 and 0.2850.285. C. Among enter your response here% of the population of all US adults, the proportion who are "cord cutters" lies between enter your response here and enter your response here. D. There is a enter your response here% chance that the true proportion of all US adults who are "cord cutters" lies between enter your response here and enter your response here. Your answer is not correct. Part 5 e. Suppose a cable TV executive claims that p=0.24. Is the claim believable? Explain. The claim ▼ believable, since 0.24 ▼ the confidence interval from part c.

A poll was conducted on a representative sample of 600 adults living in the United States in order to investigate the decline in cable and satellite TV subscriptions. For this sample, 150 adults revealed that they are "cord cutters," (that is, they canceled their cable/satellite TV service and now only use a video streaming service). You want to estimate p, the true proportion of all US adults who are "cord cutters." Complete parts a through e. Question content area bottom Part 1 a. Find p, the point estimate of p. 0.250.25 (Round to three decimal places as needed.) Part 2 b. Describe the sampling distribution of p. Select the correct choice below and fill in the answer box(es) within your choice. A. Approximately exponential with mean enter your response here and standard deviation enter your response here B. Approximately normal for large samples with mean 0.250.25 and standard deviation 0.01770.0177 (Round to four decimal places as needed.) Your answer is correct. C. Approximately a t-distribution with mean enter your response here, standard deviation enter your response here, and enter your response here degrees of freedom (Type integers or decimals rounded to four decimal places as needed.) D. Approximately Poisson with λ=enter your response here (Round to four decimal places as needed.) E. Approximately uniform with mean enter your response here and standard deviation enter your response here (Round to four decimal places as needed.) Part 3 c. Find a 95% confidence interval for p. 0.2150.215,0.2850.285 (Round to three decimal places as needed.) Part 4 d. Give a practical interpretation of the confidence interval from part c. (Type integers or decimals rounded to three decimal places as needed. Use ascending order.) A. The probability that the true proportion of all US adults who are "cord cutters" is enter your response here lies between enter your response here and enter your response here. B. We can be 9595% confident that the true proportion of all US adults who are "cord cutters" lies between 0.2150.215 and 0.2850.285. C. Among enter your response here% of the population of all US adults, the proportion who are "cord cutters" lies between enter your response here and enter your response here. D. There is a enter your response here% chance that the true proportion of all US adults who are "cord cutters" lies between enter your response here and enter your response here. Your answer is not correct. Part 5 e. Suppose a cable TV executive claims that p=0.24. Is the claim believable? Explain. The claim ▼ believable, since 0.24 ▼ the confidence interval from part c.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Question content area bottom

Part 1

a. Find

the point estimate of p.

0.250.25

(Round to three decimal places as needed.)

Part 2

b. Describe the sampling distribution of

Select the correct choice below and fill in the answer box(es) within your choice.

Approximately exponential with mean

enter your response here

and standard deviation enter your response here

Approximately normal for large samples with mean

0.250.25

and standard deviation 0.01770.0177

(Round to four decimal places as needed.)

Your answer is correct.

Approximately a t-distribution with mean

enter your response here,

standard deviation

enter your response here,

and

enter your response here

degrees of freedom

(Type integers or decimals rounded to four decimal places as needed.)

Approximately Poisson with

λ=enter your response here

(Round to four decimal places as needed.)

Approximately uniform with mean

enter your response here

and standard deviation enter your response here

(Round to four decimal places as needed.)

Part 3

c. Find a

95%

confidence interval for p.

0.2150.215,0.2850.285

(Round to three decimal places as needed.)

Part 4

d. Give a practical interpretation of the confidence interval from part

(Type integers or decimals rounded to three decimal places as needed. Use ascending order.)

The probability that the true proportion of all US adults who are "cord cutters" is

enter your response here

lies between

enter your response here

and

enter your response here.

We can be

9595%

confident that the true proportion of all US adults who are "cord cutters" lies between

0.2150.215

and

0.2850.285.

Among

enter your response here%

of the population of all US adults, the proportion who are "cord cutters" lies between

enter your response here

and

enter your response here.

There is a

enter your response here%

chance that the true proportion of all US adults who are "cord cutters" lies between

enter your response here

and

enter your response here.

Your answer is not correct.

Part 5

Suppose a cable TV executive claims that

p=0.24.

Is the claim believable? Explain.

The claim

▼

believable, since

0.24

▼

the confidence interval from part c.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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