In a program designed to help patients stop smoking, 193 patients were given sustained care, and 82.9% of them were no longer smoking after one month. Use a 0.10 significance level to test the claim that 80% of patients stop smoking when given sustained care. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution.

In a program designed to help patients stop smoking, 193 patients were given sustained care, and 82.9% of them were no longer smoking after one month. Use a 0.10 significance level to test the claim that 80% of patients stop smoking when given sustained care. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Subject : Statestic
Smoking Stopped In a program designed to help patients stop smoking, 198 patients were given sustained care, and 82.8% of them were no longer smoking after one month. Among 199 patients given standard care, 62.8% were no longer smoking after one month (based on data from “Sustained Care Intervention and Postdischarge Smoking Cessation Among Hospitalized Adults,” by Rigotti et al., Journal of the American Medical Association, Vol. 312, No. 7). Construct the two 95% confidence interval estimates of the percentages of success. Compare the results. What do you conclude?
Suppose that in a random selection of 100 colored candies, 26% of them are blue. The candy company claims that the percentage of blue candies is equal to 28%. Use a 0.01 significance level to test that claim. Identify the null and alternative hypotheses for this test. Choose the correct answer below. А. Но: р30.28 H1:p0.28 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.)
A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms. Full data set O Carpeted Uncarpeted 9.4 9.1 16 10.8 6.4 10.8 14.8 8.8 11.5 11.6 13.7 9.4 10.7 12.4 13.4 7.8 Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the a = 0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers. State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. OA Ho P1 H2 B. Ho H1 F2 OC Ho H= H2
S Identify the type I error and the type II error for a hypothesis test of the indicated claim. The percentage of adults who retire at age 65 is less than 62%. Identify the type I error. Choose the correct answer below. OA. Reject the null hypothesis that the percentage of adults who retire at age 65 is less than 62% when it is actually true. OB. Fail to reject the null hypothesis that the percentage of adults who retire at age 65 is greater than or equal to 62% when it is actually false. OC. Fail to reject the null hypothesis that the percentage of adults who retire at age 65 is less than 62% when it is actually false. OD. Reject the null hypothesis that the percentage of adults who retire at age 65 is greater than or equal to 62% when it is actually true. Get more help - 4 Q Search P Pearson 3 right © 2023 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions | Contact Us | S Clear all Check ans
Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is mu greater than 98.6 degrees F. The sample size is n equals 5 and the test statistic is t equals 1.486. P-value equals (Round to three decimal places as needed.)
The Pavalue for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a = 0.01, (b) a = 0.05. and (c)g=0 10 P=0.0816 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? O A. Fail to reject Ho because the P-value, 0.0816, is less than a = 0.01. O B. Fail to reject H, because the P-value, 0.0816, is greater than a= 0.01. OC. Reject H, because the P-value, 0.0816, is less than a=0.01. O D. Reject Ho because the P-value, 0.0816, is greater thana= 0.01. (b) Do you reject or fail to reject H, at the 0.05 level of significance? O A. Reject Ho because the P-value, 0.0816, is less than a =0.05. O B. Fail to reject H, because the P-value, 0.0816, is greater than a= 0.05. OC. Reject H, because the P-value, 0.0816, is greater than oa 0.05. O D. Fail to reject Ho because the P-value, 0.0816, is less than a = 0,05. (c) Do you reject or fail to reject Ho at the 0.10 level of significance? O A. Reject Ho because the…
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Consider a drug testing company that provides a test for marijuana usage. Among 335 tested subjects, results from 27 subjects were wrong (either a false positive or a false negative). Use a 0.05 significance level to test the claim that less than 10 percent of the test results are wrong. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p=0.1 H1:p0.1 OC. Ho: p<0.1 H1:p=0.1 O D. Ho: p=0.1 H1:p+0.1
Describe type I and type II errors for a hypothesis test of the indicated claim. A furniture store claims that at least 40% of its new customers will return to buy their next piece of furniture. Describe the type I error. Choose the correct answer below. OA. A type I error will occur when the actual proportion of new customers who return to buy their next piece of furniture is at least 0.40, but you fail to reject Ho: p20.40. OB. A type I error will occur when the actual proportion of new customers who return to buy their next piece furniture is at least 0.40, but you reject Ho: p20.40. OC. A type I error will occur when the actual proportion of new customers who return to buy their next piece of furniture is no more than 0.40, but you reject Ho: p ≤ 0.40. OD. A type I error will occur when the actual proportion of new customers who return to buy their next piece f furniture is no more than 0.40, but you fail to reject Ho: p ≤0.40. Describe the type II error. Choose the correct answer…
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