In a recent year, the scores for the reading portion of a test were normally distributed, with a mean of 21.5 and astandard deviation of 6.4. Complete parts (a) through (d) below.T(a) Find the probability that a randomly selected high school student who took the reading portion of the test has ascore that is less than 18.The probability of a student scoring less than 18 is 2912(Round to four decimal places as needed.)(b) Find the probability that a randomly selected high school student who took the reading portion of the test has ascore that is between 15.1 and 27.9.The probability of a student scoring between 15.1 and 27.9 is(Round to four decimal places as needed.)

Answered: In a recent year, the scores for the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to a recent survey, the salaries of entry-level positions at a large company have a mean of $41,750 and a standard deviation of $7000 . Assuming that the salaries of these entry-level positions are normally distributed, find the proportion of employees in entry-level positions at the company who earn at most $45,000 . Round your answer to at least four decimal places.
The lifetime risk of developing pancreatic cancer is about one in 78 (1.28%). Suppose we randomly sample 200 people. Let X = the number of people who will develop pancreatic cancer. b. Using the formulas, calculate the (i) mean and (ii) standard deviation of X. c. Use your calculator to find the probability that at most eight people develop pancreatic cancer d. Is it more likely that five or six people will develop pancreatic cancer? Justify your answer numerically.
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 77.3 Mbps. The complete list of 50 data speeds has a mean of x = 18.24 Mbps and a standard deviation of s = 17.77 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant? a. The difference is (Type an integer or a Mbps. decimal. Do not round.) b. The difference is (Round to two decimal standard deviations. places as needed.) c. The z score is z = (Round to two decimal places as needed.) d. The carrier's highest data speed is C
A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1466 and the standard deviation was 315. The test scores of four students selected at random are 1890, 1210, 2200, and 1340. Find the z-scores that correspond to each value and determine whether any of the values are unusual. The Z-score for 1890 is. (Round to two decimal places as needed.).
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 72.5 Mbps. The complete list of 50 data speeds has a mean of x=18.25 Mbps and a standard deviation of s=17.86 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The mean time taken by all participants to run a road race was found to be 110 minutes with a standard deviation of 15 minutes. Using Chebyshev's theorem, find the percentage of runners who ran this road race in 80 to 140 minutes. Round your answer to the nearest integer. of
The board of examiners that administers the real estate broker’s examination in a certain state found that the mean score on the test was 450 and the standard deviation was 50. If the board wants to set the passing scores so that only the top 5% of all applicants pass, what should the passing score be? Assume that the scores are normally distributed.
A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1471 and the standard deviation was 317. The test scores of four students selected at random are 1900,1200,2200,and 1370. Find the z-scores that correspond to each value and determine whether any of the values are unusual.
Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 27 and the age of the winner for best actress were 47. For all best actors, the mean age is 42.7 years and the standard deviation is 7.7 years. For all best actresses, the mean age is 32.9 years and the standard deviation is 11.2 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z= and the z score for the actress is z=,the▼actress actor had the more extreme age.
Use z scores to compare the given values. The tallest living man at one time had a height of 252 cm. The shortest living man at that time had a height of 53.2 cm. Heights of men at that time had a mean of 172.68 cm and a standard deviation of 8.46 cm. Which of these two men had the height that was more extreme? see score past due Since the z score for the tallest man is z=] and the z score for the shortest man is z= the height that was more extreme. (Round to two decimal places.)
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 73.7 Mbps. The complete list of 50 data speeds has a mean of x = 16.05 Mbps and a standard deviation of s = 17.75 Mbps. a. What is the difference between carrier's highest data speed and the mean of all 50 data speeds? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the carrier's highest data speed to a z score. d. If we consider data speeds that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant? ..... a. The difference is Mbps. (Type an integer or a decimal. Do not round.) b. The difference is standard deviations. (Round to two decimal places as needed.) c. The z score is z = (Round to two decimal places as needed.) d. The carrier's highest data speed is Next MacBook F12 DD F11 DII F10 F9 F8 888 00 F7 F6 F5 F4 F3 F2 F1 & ! @ # $ 7 8 4 5 6…

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