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In a portion of the square, 2-D finite difference mesh shown, node 2 is located on an insulated edge. The thickness and thermal conductivity of the region are 1.50 mm and 20 W/m-K, respectively. If there is a point heat source of 1.2 W at node 2, calculate the steady temperature of node 2. T, = 40°C T = 52°C T= 60°C 0,= 1.2 W 8 = 1.50 mm k= 20 W/m·K 3

In a portion of the square, 2-D finite difference mesh shown, node 2 is located on an insulated edge. The thickness and thermal conductivity of the region are 1.50 mm and 20 W/m-K, respectively. If there is a point heat source of 1.2 W at node 2, calculate the steady temperature of node 2. T, = 40°C T = 52°C T= 60°C 0,= 1.2 W 8 = 1.50 mm k= 20 W/m·K 3

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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In a portion of the square, 2-D finite difference mesh shown, node 2 is located on an insulated edge. The thickness and thermal conductivity of the region are 1.50 mm and 20 W/m-K, respectively. If there is a point heat source of 1.2 W at node 2, calculate the steady temperature of node 2. 5. T = 40°C 1 T; = 52°C T = 60°C Q,= 1.2 W 4 2 8 = 1.50 mm k = 20 W/m K 3
Transcribed Image Text:In a portion of the square, 2-D finite difference mesh shown, node 2 is located on an insulated edge. The thickness and thermal conductivity of the region are 1.50 mm and 20 W/m-K, respectively. If there is a point heat source of 1.2 W at node 2, calculate the steady temperature of node 2. 5. T = 40°C 1 T; = 52°C T = 60°C Q,= 1.2 W 4 2 8 = 1.50 mm k = 20 W/m K 3
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