in a particular ecosystem, we expect the ratio of juvenile, mature and senescent mayflies to be 1:2:1, respectively. A sample of 368 mayflies were observed and their life cycle stage were recorded in the table below. Juvenile Mature Senescent Observed 84 176 108 a) Calculate the expected number of juvenile mayflies. Give your answer as a whole number. b) Calculate the expected number of mature mayflies. Give your answer as a whole number. c) Calculate the expected number of senescent mayflies. Give your answer as a whole number.
Contingency Table
A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.
Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
in a particular ecosystem, we expect the ratio of juvenile, mature and senescent mayflies to be 1:2:1, respectively. A sample of 368 mayflies were observed and their life cycle stage were recorded in the table below.
Juvenile Mature Senescent
Observed 84 176 108
a)
Calculate the expected number of juvenile mayflies. Give your answer as a whole number.
b)
Calculate the expected number of mature mayflies. Give your answer as a whole number.
c)
Calculate the expected number of senescent mayflies. Give your answer as a whole number.
d)
Calculate the chi square goodness of fit (?2 ) test statistic for this dataset. Give your answer to 2 decimal places.
e)
State the critical value for this test. (See table on 'On-line' exam tab.) State your answer to 2 decimal places.
f)
In this test the null hypothesis is that there is NOT a difference between observed and expected frequencies. Which of these should you do?
Reject the null (i.e. there is a significant difference between observed and expected frequencies).
Fail to reject the null (i.e. there is NOT a significant difference between observed and expected frequencies).
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