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In a normal distribution:
The shape of the distribution is ["", ""] ,
the dispersion is ["", "", ""] ,
and the peaks are described as ["", "", ""] .
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- We know that tao boolean input variables can have 16 unique boolean functions. How many unique boolean function can we have given 3 input variable and n variables?3.) Given this truth table, find the unoptimized formula this corresponds to, along with the version which was optimized with a K-Map. A B C D O 0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 0 1 0 1 0 1 1 0 0 1 1 1 1 0 0 0 1 0 0 1 1 0 1 0 1 0 1 1 1 1 0 0 1 1 0 1 1 1 1 0 1 1 1 1 1 1 1 1 1 0 0 0 1 0 0 0 1 0 0 0 Unoptimized Sum of Products equation 3a) 0 = Draw the K-map and simplify Optimized Sum of Products equation 3b) 0 =1) The truth table of function fis given below left. Please complete its k-map in the right. XI X2 X3 X3
- Two x-ray images of the hand are shown. One corresponds to an x-ray beam with an effective energy of a) 140 keV and the other to an effective energy of b) 50 keV. Identify which is which, and the reasons for the differences in the image contrast and signal intensity. a.None of the above. b.The attenuation coefficient does not gives rise to contrast in x-ray imaging and is not energy dependent. At 50 keV the attenuation coefficient is about the same between tissues and bone showing no contrast, whereas at 140 keV there is a greater difference between tissues showing greater contrast. c.The attenuation coefficient gives rise to contrast in x-ray imaging and is energy dependent. At 140 keV the attenuation coefficient is about the same between tissues and bone showing no contrast, whereas at 50 keV there is a greater difference between tissues showing greater contrast. d. The attenuation coefficient gives rise to contrast in x-ray imaging and is energy dependent. At 50 keV the attenuation…An aluminum wire having a cross-sectional area equal to 4.60 x 10-6 m? carries a current of 7.50 A. The density of aluminum is 2.70 g/cm³. Assume each aluminum atom supplies one conduction electron per atom. Find the drift speed of the electrons in the wire. 1.95E-4 The equation for the drift velocity includes the number of charge carriers per volume, which in this case is equal to the number of atoms per volume. How do you calculate that if you know the density and the atomic weight of aluminum? mm/sGiven is a sine wave in time domain, using this wave plots answer the following: 1 second ww. Time A- How much is the wave amplitude with its unit? Answer B- How much is the wave frequency with its unit? Answer C- Draw the same wave in the frequency domain Answer
- Given two Boolean functions T: and T2 with the truth table in Figure 1. B T1 イ2 0. 1 1 1 1 1 1 1 1 1 0. 1 1 1 1 1 1 1 1 1 1 1 Figure 1. The truth table for Problem #2. Simplify these functionsCompute the following values of ψ(X, B), the number of B-smooth numbers between 2 and X. (c) ψ(50, 7)1. Given the following truth table: с F 1 A В 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 a) Write down the minterm expansion for the function F b) Draw the K-Map using the minterm expansion
- This is discrete math:Find the derivative of the function. F(x) = -1/12/2 x2 f'(x) =2. calculates the trajectory r(t) and stores the coordinates for time steps At as a nested list trajectory that contains [[xe, ye, ze], [x1, y1, z1], [x2, y2, z2], ...]. Start from time t = 0 and use a time step At = 0.01; the last data point in the trajectory should be the time when the oscillator "hits the ground", i.e., when z(t) ≤ 0; 3. stores the time for hitting the ground (i.e., the first time t when z(t) ≤ 0) in the variable t_contact and the corresponding positions in the variables x_contact, y_contact, and z_contact. Print t_contact = 1.430 X_contact = 0.755 y contact = -0.380 z_contact = (Output floating point numbers with 3 decimals using format (), e.g., "t_contact = {:.3f}" .format(t_contact).) The partial example output above is for ze = 10. 4. calculates the average x- and y-coordinates 1 y = Yi N where the x, y, are the x(t), y(t) in the trajectory and N is the number of data points that you calculated. Store the result as a list in the variable center = [x_avg, y_avg]…