In a mass spectrometer, a doubly charged ion having a particular velocity is selected by using a magnetic field of 70 mT perpendicular to an electric field of 2.3 kV/m. The same magnetic field is used to deflect the ion in a circular path with a radius of 88 mm. What is the mass of the ion?The mass, m = \(8.0 \times 10^{-25}\) kg. Units: kg. (Note: In the image, the mass value is confirmed as correct with a checkmark, while the units box indicates "kg" selected as the unit.)

Given : q = 2e = 2(1.6 × 10-19) = 3.2 × 10-19 C B = 70 mT = 0.07 T E = 2.3 kV/m = 2.3 × 103 V/m r = 88 mm = 0.088 mAt equilibrium : Electric force = Magnetic force qE = qvB E/B = v v = 2.3 × 103/0.07 v = 3.286 × 104 m/s Also, Magnetic force = Centripetal force qvB = mv2/r Therefore, m = qBr/v m = (3.2 × 10-19)(0.07)(0.088)/(3.286 × 104) m = 6.0 × 10-26 kg >>>> Answer

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In a mass spectrometer, a doubly charged ion having a particular velocity is selected by using a magnetic filed of 70 mT perpendicular to an electric field of 2.3 kV/m. The same magnetic field is used to deflect the fon in a circular path with a radius of 88 mm. What is the mass of the ion? The mass, m = 6.0E-25 x Units kg

In a mass spectrometer, a doubly charged ion having a particular velocity is selected by using a magnetic filed of 70 mT perpendicular to an electric field of 2.3 kV/m. The same magnetic field is used to deflect the fon in a circular path with a radius of 88 mm. What is the mass of the ion? The mass, m = 6.0E-25 x Units kg

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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