In a Leichtman Research Group survey of 1000 TV households, 74.5% of them had at least one Internet-connected TV device (for example, Smart TV, standalone streaming device, connected video game console). A marketing executive wants to convey high penetration of Internet-connected TV devices, so he makes the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 82%. Test that claim using a 0.05 significance level. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution.---Let $ p $ denote the population proportion of all homes with at least one Internet-connected TV device. Identify the null and alternative hypotheses.- $ H_0: p $ [dropdown] [box]- $ H_1: p $ [dropdown] [box] *(Type integers or decimals. Do not round.)*Identify the test statistic.- $ z = $ [box] *(Round to two decimal places as needed.)*Identify the P-value.- P-value = [box] *(Round to three decimal places as needed.)*State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim.- [dropdown] the null hypothesis. There [dropdown] sufficient evidence to [dropdown] the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 82%.

Givensample proportion(p^)=0.745sample size(n)=1000significance level(α)=0.05

Answered: In a Leichtman Research Group survey of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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